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Yuki888 [10]
2 years ago
11

The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of G

lob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down. Initial speed of the rock = 1.92×101 m/s. (Glob has no atmosphere, so no energy is lost to air friction. G = 6.67×10-11 Nm2/kg2.)
A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Calculate the speed of the satellite.
Physics
1 answer:
timama [110]2 years ago
6 0

The orbiting speed of the satellite orbiting around the planet Glob is 60.8m/s.

To find the answer, we need to know about the orbital velocity a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
  • Mathematically, orbital velocity= √(GM/r)
  • G= gravitational constant= 6.67×10^(-11) Nm²/kg², M = mass of sun , r= radius of orbit

<h3>What's the orbital velocity of the satellite in a circular orbit with a radius of 1.45×10⁵ m around the planet Glob of mass 7.88×10¹⁸ kg?</h3>
  • Here, M= 7.88×10¹⁸ kg, r= 1.45×10⁵ m
  • Orbital velocity of the orbiting satellite = √(6.67×10^(-11)×7.88×10¹⁸/1.45×10⁵)

= 60.8m/s

Thus, we can conclude that the speed of the satellite orbiting the planet Glob is 60.8m/s.

Learn more about the orbital velocity here:

brainly.com/question/22247460

#SPJ1

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A particle moves at a constant speed of 34 m/s in a circular path of radius 6.3 m. From this information, what can be calculated
Yakvenalex [24]

Answer:

Centripetal acceleration

Explanation:

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  • <em><u>Centripetal acceleration is given by; the square of the velocity, divided by the radius of the circular path. </u></em>
  • That is;

         ac = v²/r

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a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac
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A bird flies 2 km to the south then 0.2 km to the north . What is the displacement of the bird?
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An object carries a +15.5 µC charge. It is 0.525 m from a -7.25 µC charge. What is the magnitude of the electric force on the ob
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Answer:

the force of attraction between the two charges is 3.55 N.

Explanation:

Given;

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distance between the two charges, r = 0.525 m

The force of attraction between the two charges is calculated as;

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