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tatyana61 [14]
3 years ago
7

A cross-country skier moves 32 meters westward, then 54

Physics
1 answer:
tigry1 [53]3 years ago
3 0

Explanation:

It is given that, a cross-country skier moves 32 meters westward, then 54  meters eastward, and finally 68 meters westward.

The attached figure shows the whole scenario. He starts walking 32 m west and finally it walks 68 m west.

Let west is negative and east is positive.

Displacement = final position - initial position

= -68 - (-32)

= -36 m

The magnitude of displacement is equal to 30 m westwards.

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Answer:

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Explanation:

Given;

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extention of the spring, x = 5 mm = 5 x 10⁻³ m

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The weight of the driver is calculated as;

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F = 68 x 9.8 = 666.4 N

The spring constant, k, is calculated as;

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The angular speed of the spring is calculated;

\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s

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f = (9.426) / (2π)

f = 1.5 Hz

Therefore, the frequency of the oscillation is 1.5 Hz

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