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katovenus [111]
3 years ago
14

True or false. Lateral to the inguinal region is the coxal region, while superior to the scapular region is the dorsal region.

Physics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

false

Explanation:

false

false

The right answer is false

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The mass of this astronaut on the moon is 84kg. If the astronaut is on the moon for 3 weeks then returns home, his mass will be
saul85 [17]

Answer:

84kg

Explanation:

If the mass of an astronaut in on the moon is 84kg on the moon. After the 3weeks in returning home, his weight will not change. The mass of the astronaut will remain the same which is 84kg. This is so because the acceleration due to gravity experienced by the body remains the same both in the earth and in moon.

7 0
3 years ago
What is 75 miles per hour (mi/h) in meters per second (m/s)? 1 mile = 1.6 km.
Sedbober [7]

Answer:33.33 m/s

Explanation: In order to calculate this conversion we have to use:

1 mile = 1.6 km and also to convert Km/h to m/s the factor is 1000/3600

then we have: 75*1.6*0.27=33.33 m/s

8 0
3 years ago
Do you think most people follow the recommended guidelines for an adequate exercise routine?
blondinia [14]

Personally, I know that I don't however it all depends on the person's lifestyle, health, and resoucres, such as if they are able to complete the excersise or have enough money fore equpemnt. To be safe, I would say that the majority of people do follow the guidelines although they may manipulate it to fit their best interest.

6 0
3 years ago
Which is the function of a nucleus within a eukaryotic cell?
DerKrebs [107]
ANSWER
D) store genetic information that provides instructions for the cell
6 0
3 years ago
The Bullet Train The Shinkansen, the Japanese "bullet" train, runs at high speed from Tokyo to Nagoya. Riding on the Shinkansen,
jeyben [28]

Answer:

68.6 m/s

Explanation:

v = Speed of sound in air = 343 m/s

u = Speed of train

f_1 = Actual frequency

From the Doppler effect we have the observed frequency as

When the train is approaching

f=f_1\frac{v+u}{v}

When the train is receeding

\frac{2f}{3}=f_1\frac{v-u}{v}

Dividing the above equations we have

\frac{f}{\frac{2f}{3}}=\frac{f_1\frac{v+u}{v}}{f_1\frac{v-u}{v}}\\\Rightarrow \frac{3}{2}=\frac{v+u}{v-u}\\\Rightarrow 3v-3u=2v+2u\\\Rightarrow v=5u\\\Rightarrow u=\frac{v}{5}\\\Rightarrow u=\frac{343}{5}\\\Rightarrow u=68.6\ m/s

The speed of the train is 68.6 m/s

5 0
3 years ago
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