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katovenus [111]
3 years ago
14

True or false. Lateral to the inguinal region is the coxal region, while superior to the scapular region is the dorsal region.

Physics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

false

Explanation:

false

false

The right answer is false

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Chemical properties of an acid include...
Igoryamba
This is a list of well known characteristics of acids:

1) acids increase the concentration of hydronum ions ([H3O+]) when dissolved in water

2) acids taste sour

3) many are corrosive (the higher the acidity the higher the corrosive property)

4) when acids react with some metals produce hydrogen gas

5) acids conduct electricity (due to the presence of hydronium ions)

6) acids neutralize bases

7) acids combine with bases to produce water and salt

8) acids lower the pH of solutions.

They do not feel sticky to the touch. Bases fell slippery but there is not that property of sticky sensation about acids, although some highly concentrated strong acids have high viscosity. You cannot touch highly concentrated strong acids.


8 0
3 years ago
Read 2 more answers
What is most likely the relationship between Mendel’s rules of genetics and Darwin’s idea of biological evolution?
xenn [34]

Answer:

Darwin's theory of natural selection lacked an adequate account of ... Darwinian principles now play a greater role in biology than ever before, .... Sadly, even if Mendel had lived to see the rediscovery of his work, he probably .... evolutionary forces are acting, a genetic equivalent to Galileo's law of inertia.

Explanation:

4 0
3 years ago
A 5.30kg block hangs from a spring with a spring constant 1700 N/m. The block is pulled down 4.50cm from the equilibrium positio
Andru [333]

To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

PART A) By definition the frequency in a spring is given by the equation

f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}

Where,

m = mass

k = spring constant

Our values are,

k=1700N/m

m=5.3 kg

Replacing,

f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}

f=2.85 Hz

PART B) To solve this section it is necessary to apply the concepts related to the conservation of energy both potential (simple harmonic) and kinetic in the spring.

\frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2} kY^2

Where,

k = Spring constant

m = mass

y = Vertical compression

v = Velocity

This expression is equivalent to,

kA^2 =mV^2 +ky^2

Our values are given as,

k=1700 N/m

V=1.70 m/s

y=0.045m

m=5.3 kg

Replacing we have,

1700*A^2=5.3*1.7^2 +1700*(0.045)^2

Solving for A,

A^2 = \frac{5.3*1.7^2 +1700*(0.045)^2}{1700}

A ^2 = 0.011035

A=0.105 m \approx 10.5 cm

PART C) Finally, the total mechanical energy is given by the equation

E = \frac{1}{2}kA^2

E=\frac{1}{2}1700*(0.105)^2

E= 9.3712 J

3 0
3 years ago
A pendulum is lifted to a certain height and then released, which causes the
borishaifa [10]

Answer:

Answer is C

Explanation:

Let's say the pendulum starts swinging from its max height from the left. It then will go down and reach the equilibrium position, this will make it lose GPE while gaining KE (the loss in GPE = gain in KE). At the equilibrium position it has the max KE (max velocity) and minimum GPE. After passing the equilibrium it then starts to head up to the max height on the right, the pendulum gains GPE while losing KE and at the top will have minimum KE while having max GPE. Meaning throughout its joruney the total energy remains constant as
Total energy = KE + GPE

I have attached a simple diagram below, the y axis is the energy and x axis being the time (where t = 0 is the pendulum starting from max height left of the equilibrium). The green curve the the GPE and blue curve is KE. Red line shows that at all times the energy is constant.

8 0
2 years ago
What needs to be the relation between the two forces to cause the upper magnet to float without moving?
OleMash [197]

Answer:

If it points the other way, the fields subtract, for a lower energy, and so the magnet prefers to turn to point in this way. Magnets in uniform fields feel torques which make them turn around if they are not pointing in the right direction, but there is no net force making the magnet want to levitate.

Explanation:

7 0
3 years ago
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