Answer:
W = 0.49 N
τ = 0.4851 Nm
Force
Explanation:
The weight force can be found as:
W = mg
W = (0.05 kg)(9.8 m/s²)
<u>W = 0.49 N</u>
The torque about the pivot can be found as:
τ = W*d
where,
τ = torque
d = distance between weight and pivot = 99 cm = 0.99 m
Therefore,
τ = (0.49 N)(0.99 m)
<u>τ = 0.4851 Nm</u>
The pivot exerts a <u>FORCE </u>on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.
Answer:
Plzzzzzzzzzzzzzzzz brainliest
Explanation:
In static friction, the frictional force resists force that is applied to an object, and the object remains at rest until the force of static friction is overcome. In kinetic friction, the frictional force resists the motion of an object. ... The frictional force itself is directed oppositely to the motion of the object.
The work done by the centripetal force during om complete revolution is 401.92 J.
<h3>What is centripetal force?</h3>
Centripetal force is a force that acts on a body undergoing a circular motion and is directed towards the center of the circle in which the body is moving.
To Calculate the work done by the centripetal force during one complete revolution, we use the formula below.
Formula:
- W = (mv²/r)2πr
- W = 2πmv²................... Equation 1
Where:
- W = Work done by the centripetal force
- m = mass of the ball
- v = velocity of the ball
- π = pie
From the question,
Given:
- m = 16 kg
- v = 2 m/s
- π = 3.14
Substitute these values into equation 1
Hence, The work done by the centripetal force during om complete revolution is 401.92 J.
Learn more about centripetal force here: brainly.com/question/20905151
Answer:
option D
Explanation:
given,
A conductor is carrying current = 2.0 A is 0.5 mm thick
Hall voltage = 4.5 x 10-6 V
uniform magnetic field = 1.2 T
density of the charge = n =?
hall voltage =
n = 6.67 × 10²⁷ charges/m
hence the correct answer is option D
