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Alika [10]
2 years ago
7

Fire spreading from a wall to a nearby couch due to radiant heat transfer is an example of: Select one:

Physics
1 answer:
Mrac [35]2 years ago
6 0

Fire spreading from a wall to a nearby couch due to radiant heat transfer is an example of heat reflectivity.

<h3>What is heat reflectivity?</h3>

When sunlight and other light sources strike a material's surface, its reflectance is measured. This number can be used to characterize a surface's characteristics in terms of surface finish. Another name for reflection is reflectivity.

This is a measurement of the amount of energy that material reflects at a specific wavelength. A value between 0 and 1 can also be used to represent reflectivity (or a percentage between 0 and 100).

Sigma and other top businesses have created a range of other forms of heat reflective fabric in the 50 years after the creation of space blankets, including Fabric and aluminum foil laminates, fabric laminates with metalized thin films.

Learn more about heat reflectivity here:

brainly.com/question/26105866

#SPJ4

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Two point charges are brought closer together, increasing the force between them by a factor of 20. By what factor was their sep
olga55 [171]

The separation between them is \frac{r}{\sqrt{20} }

Concept :

If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.

Given,

Two point charges are brought closer together, increasing the force between them by a factor of 20.

Original force is

F = \frac{kq_{1} q_{2} }{r^{2} } -------- ( 1 )

Here, q_{1} , q_{2} are charges and r is the distance between them

New force F' = \frac{kq_{1q_{2} } }{r'^{2} } ----------- (2 )

Divide ( 1 ) and ( 2 )

\frac{F'}{F} = \frac{\frac{kq_{1}q_{2}  }{r'^{2} } }{\frac{kq_{1}_{2}  }{r^{2} } }

20 = \frac{r^{2} }{r'^{2} }

r' = \frac{r}{\sqrt{20} }

Given that force between them are increasing and therefore distance between them decrease by \frac{r}{\sqrt{20} }

Learn more about two point charges here : brainly.com/question/24206363

#SPJ4

8 0
2 years ago
You obtain a spectrum of an object in space. The spectrum consists of a number of sharp, bright emission lines. Is this object a
Andreyy89

Answer:

In hot gases , the atoms keeps colliding with each other and sometimes the energy liberated during collision takes the electron to a higher level,thus, .The object is a cloud of hot gas and finally the electron returns back emitting photon

6 0
3 years ago
Read 2 more answers
A pendulum makes 40 vibrations in 20 seconds. calculate it's period?
DiKsa [7]

(20 seconds / 40 vibes) = (20/40) (seconds/vibe) =  0.5 second
3 0
4 years ago
Read 2 more answers
The moon Phobos orbits Mars
shepuryov [24]

27.9816 \times 10^{3} s is the period of orbit.

<u>Explanation: </u>

The equation that is useful in describing satellites motion is Newton form after Kepler's Third Law. The period of the satellite (T) and the average distance to the central body (R) are related as the following equation:

                  \frac{T^{2}}{R^{3}}=\frac{4 \times \pi^{2}}{G \times M_{c e n t r a l}}

Where,

T is the period of the orbit

R is the average radius of orbit

G is gravitational constant  6.673 \times 10^{-11} \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}

Here, given data

M=6.23 \times 10^{23} \mathrm{kg}

R=9.38 \times 10^{6} \mathrm{m}

Substitute the given values, we get T as

      \frac{T^{2}}{\left(9.38 \times 10^{6}\right)^{3}}=\frac{4 \times(3.14)^{2}}{\left(6.673 \times 10^{-11}\right) \times 6.23 \times 10^{23}}

      T^{2}=\frac{4 \times 9.8596 \times 825.29 \times 10^{18}}{41.57 \times 10^{12}}

      T^{2}=\frac{32548.12 \times 10^{18-12}}{41.57}=782.97 \times 10^{6}

Taking square root, we get

       T=27.9816 \times 10^{3} s

4 0
3 years ago
find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​
Mazyrski [523]

Answer:

0.02

Explanation:

Force, F=\mu_k N where N is normal reaction and coefficient of kinetic friction is \mu_k. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making \muthe subject of the formula then

\mu_k=\frac {F}{mg}

Substituting F with 2 N, m with 10 kg and g with 9.81 then

\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02

5 0
4 years ago
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