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ki77a [65]
2 years ago
15

2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.

Physics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

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The stopping sight distance for a car traveling at 50 mph is 461 ft (including both perception-reaction distance and braking dis
Ivan

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Yo-Yo man releases a yo-yo from rest and allows it to drop, as he keeps the top end of the string stationary. The mass of the yo
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To solve this problem it is necessary to use the conservation equations of both kinetic, rotational and potential energy.

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KR = Rotational Kinetic Energy

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In this way

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