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ki77a [65]
2 years ago
15

2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.

Physics
1 answer:
Ira Lisetskai [31]2 years ago
8 0

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

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Answer:

electricfield at (0,0,0) is Et = 2 k q / a²

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If we use the condition that  R> a we can despise in the patents "a"

     (R² + a²) = R² (1+ a² / R²) ≈ R²

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     (R- a)²  = R² (1-a / R)² ≈ R²

Substituting in the total electric field

     Et = kq {2 R²) / [R²R²]}

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