The force exerted by a pressure of any gas over a surface its given by the formula P=F/S (where P is pressure, F force and S surface).
We can multiply both sides of the formula by S to obtain the force.
P*S=(F*S)/S
P*S=F
Solve for P=1.80*10^5 Pa and S=4.10*10^-4 m^2 ([Pa] =[N/m^s])
(1.80*10^5 N/m^s) * (4.10*10^-4 m^2) =F
73.8 N =F
You give the ball to the other team
<span>Socialization is a way of interacting to
other people and in return, gaining insights as well as part of learning
process. Above choices are all agents of socialization so that is letter D: all
of the above. A grandparent can teach you lessons of his experiences in life
since he is older than you. Television is a medium to be able to know how to
interact with people by basing on it and learning with whatever is shown.
School is an area where different people of different ages convene and learn
together. This give you the opportunity to learn from different personalities
of ages and experiences.</span>
Answer:
Newton (N)
Explanation:
A newton is the unit of measurement for force
Answer:
Speed = 575 m/s
Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.
Explanation:
Given :
Potential difference, U = 
Mass of the alpha particle, 
Charge of the alpha particle is, 
So the potential difference for the alpha particle when it is accelerated through the potential difference is

And the kinetic energy gained by the alpha particle is

From the law of conservation of energy, we get





The mechanical energy is conserved in the presence of the following conservative forces :
-- electrostatic forces
-- magnetic forces
-- gravitational forces