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KATRIN_1 [288]
3 years ago
8

A vertical spring stretches 4.4 cm when a 16-g object is hung from it. the object is replaced with a block of mass 22 g that osc

illates up and down in simple harmonic motion. calculate the period of motion.
Physics
1 answer:
Yuri [45]3 years ago
7 0
Using K= mg/x
where k is a unction of the construction of the spring and has nothing to do with the mass attached to it;
k = 0.016 × 9.81 / 0.044
   = 3.57 N/M
when  a mass of 22 g is used the system will oscillate with a period T = 2π √(m/k)
= 2 × 3.14 ×√ 0.025/3.57)
= 6.28 × 0.0837
= 0.5255
Therefore, the period will be 0.5255 seconds
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A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string i
Firdavs [7]

Answer:

a  

The tension in the string is  T = 0.85 N

 b

 The new balance reading is  M_b  =  885.86 g

Explanation:

From the question we are told that

    The mass of the beaker of water is  m = 875 .0g

     The diameter of the copper ball is  d = 2.75 cm = \frac{2.75}{100} = 0.0275 m

There are two forces acting on the copper ball

   The first is the Buoyant force of the water pushing it up which is mathematically represented as

                     F = \rho V g

Where \rho is the density of water which has value of  \rho = 1000 kg/m^3

            g is the acceleration due to gravity g= 9.8 \  m/s^2

          V is the volume of water displaced by the copper ball  which is mathematically evaluated as

                             V = \frac{4}{3}  \pi r^3

The radius r is  r = \frac{d}{3}  = \frac{0.0275}{2} = 0.01375 m

Substituting value  

                        V = \frac{4}{3} * 3.142 * (0.01375)^3

                            V = 1.08 9 *10^{-5 } m^3  

   Substituting for  F

              F = 1000 * 1.089 *10^{-5} * 9.8

               F = 0.1067 N      

     The second force is the weight of the copper ball which is mathematically represented as

       W_c = mg

Now m is the mass which can be mathematically evaluated as

        m =  \rho_c * V

Where  is the density of copper with  value of  \rho_c = 8960 kg /m^3

So      m = 8960 * 1.089 *10^{-5}

         m = 0.0976

So the weight of copper is  

             W_c = 0.09756  *  9.8

            W_c = 0.956 N

Now the tension the string would be mathematically evaluated as

            T = W_c - F

So        T = 0.956 - 0.1067

           T = 0.85 N

From this value we that the string is holding only 0.85 N of the copper weight thus (0.956 - 0.85 = 0.1065 N ) is being held by the balance

Now the mass equivalent of this weight is mathematically evaluated as

             m_z = \frac{1.0645 }{9.8 }

             m_z = 0.01086 kg

Converting to grams  

                     m_z = 10.86 g

So the new balance reading is  

                  M_b  =  875.0 +10.86

                  M_b  =  885.86 g

5 0
3 years ago
A rock on the ground weighs 40N. How much force does the ground exert on the rock?
worty [1.4K]

Answer:

The correct option is;

C. 40 N

Explanation:

Given that the rock is on the ground, we have;

The weight of the rock, F_W = 40 N ↓

From Newton's third law of motion, we have that action and reaction are equal and opposite,

Therefore, given that the weight of the rock exerts a force of 40 N on the ground, and the rock is stable and stationery on the ground, then the ground is reacting to the weight of the rock with an equal force of 40 N, acting in opposite direction to the weight of the block to balance the weight of the rock and create equilibrium such that the net force acting on the rock is zero

∑F = F_W + F_R = 0

Where;

F_R = The reaction of the ground

We have;

F_W + F_R= 40 + F_R  = 0

F_R = 0 - 40 = -40

F_R = -40 N ↓

∴ F_R = 40 N ↑.

5 0
3 years ago
Which apparatus Is used to determine the volume of a small block of unknown material
Aleks04 [339]

Options are;

A: measuring cylinder, metre rule

B: measuring cylinder, stopwatch

C: metre rule, balance

D: metre rule, stopwatch

Answer:

A: measuring cylinder, metre rule

Explanation:

Usually, when measuring volume of a small material, we make use of a piece of laboratory apparatus known as measuring cylinder which is also known as graduated cylinder.

Since it is a graduated cylinder, it means we will make use of metre rule.

Thus, the correct option is option A.

8 0
3 years ago
_____ is the sum of all potential and kinetic energy.
Darina [25.2K]

Answer:

mechanical energyis the sum of all potential and kinetic energy.hope it helps!

4 0
3 years ago
You are handed two mystery materials, and told to find out which materials accepts negative charges more easily. A positively-ch
frutty [35]

The simple experiment you could run to find out which material accepts electrons more easily is to rub them together and move the two charge misery materials one after the other to the positive - charge helium - filled balloon.

According to the fundamental law of static electricity which state that unlike charges attract each other while like charges repel.

The simple experiment you could run if you are handed two mystery materials, and told to find out which materials accepts negative charges more easily charging by friction.

This can be employed by rubbing the two misery materials together and move them one by one to a  positively-charged, helium-filled balloon which is tied to a tabletop with a string of a meter long.

The misery material that accepts electron more easily will be attracted to the positive - charge helium - filled balloon. While the gravitational pull will pull down the other misery material. The attraction  will not be effective.

Learn more about static charges here: brainly.com/question/14210347

8 0
2 years ago
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