The vibrations of the fields are at 90° angles to the direction of the motion of the wave
<span>At any particular time of day on June 23, sunlight will fall on the
northern hemisphere more directly than the southern hemisphere,
and on the north pole more directly than the south pole. (In fact,
at that time, the south pole will be halfway through a 6-month period
of no sunlight at all.)
On June 23, the sun will appear to be directly over the parallel
of 23.5</span>° north latitude<span>, or nearly so ... the farthest north that the
sun ever appears to be.</span>
F - F(friction) = m.a
50cos(30) - F(friction) = 20 x 0.5
F(frictions) = 50cos(30) - 10 = 33.3 N
The electric field between plates is 4000V/m.
An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles.
The value of the electric field has dimensions of force per unit charge. In the metre-kilogram-second and SI systems, the appropriate units are newtons per coulomb, equivalent to volts per metre.
The voltage between points A and B is
V=E.d
E =V/d (uniform E- field only)
where d is the distance from A to B, or the distance between the plates.
Given:
distance d = 3 cm
voltage V = 120 V
Electric field E = V/d
E = 120 V / 3cm
E = 40 V / 1 cm [ 1 cm = 1/100 m ]
E = 4000 V/m.
Learn more about Electric field here:
brainly.com/question/8971780
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Answer:
h> 2R
Explanation:
For this exercise let's use the conservation of energy relations
starting point. Before releasing the ball
Em₀ = U = m g h
Final point. In the highest part of the loop
Em_f = K + U = ½ m v² + ½ I w² + m g (2R)
where R is the radius of the curl, we are considering the ball as a point body.
I = m R²
v = w R
we substitute
Em_f = ½ m v² + ½ m R² (v/R) ² + 2 m g R
em_f = m v² + 2 m g R
Energy is conserved
Emo = Em_f
mgh = m v² + 2m g R
h = v² / g + 2R
The lowest velocity that the ball can have at the top of the loop is v> 0
h> 2R
