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KATRIN_1 [288]
3 years ago
8

A vertical spring stretches 4.4 cm when a 16-g object is hung from it. the object is replaced with a block of mass 22 g that osc

illates up and down in simple harmonic motion. calculate the period of motion.
Physics
1 answer:
Yuri [45]3 years ago
7 0
Using K= mg/x
where k is a unction of the construction of the spring and has nothing to do with the mass attached to it;
k = 0.016 × 9.81 / 0.044
   = 3.57 N/M
when  a mass of 22 g is used the system will oscillate with a period T = 2π √(m/k)
= 2 × 3.14 ×√ 0.025/3.57)
= 6.28 × 0.0837
= 0.5255
Therefore, the period will be 0.5255 seconds
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The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?
BigorU [14]

1. Frequency: 7.06\cdot 10^{14} Hz

The frequency of a light wave is given by:

f=\frac{c}{\lambda}

where

c=3\cdot 10^{-8} m/s is the speed of light

\lambda is the wavelength of the wave

In this problem, we have light with wavelength

\lambda=425 nm=425\cdot 10^{-9} m

Substituting into the equation, we find the frequency:

f=\frac{c}{\lambda}=\frac{3\cdot 10^{-8} m/s}{425\cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2. Period: 1.42 \cdot 10^{-15}s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

The frequency of this light wave is 7.06\cdot 10^{14} Hz (found in the previous exercise), so the period is:

T=\frac{1}{f}=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


4 0
3 years ago
Read 2 more answers
A trailer truck with a 2000 [kg] cab and a 8000 [kg] trailer is traveling on a level road at 90 [km/hr].The brakes on the traile
NeX [460]

Answer:

a)   t = 19.6 s, b) fr = 1.274 10⁴ N

Explanation:

This is a Newton's second law problem

Y Axis

for the cabin

        N₁-W₁ = 0

        N₁ = W₁

for the trailer

        N₂- W₂ = 0

        N₂ = W₂

X axis

for the cabin plus trailer, where friction is only in the cabin

         fr = (m₁ + m₂) a

the friction force equation is

        fr = μ N

we substitute

       μ N₁ = (m₁ + m₂) a

        μ m₁ g = (m₁ + m₂) a

        a = μ g    \frac{m_1}{m_1 + m_2}

         

let's calculate

         a = 0.65 9.8    \frac{2000}{2000+8000}

         a = 1,274 m / s²

a) to find the stopping distance we can use kinematics

         Let's slow down the sI system

         v₀ = 90 km / h (1000 m / 1km) (1h / 3600s) = 25 m / s

         v = v₀ - a t

when it is stopped its speed is zero

           0 = v₀ - at

           t = v₀ / a

           t = 25 / 1.274

           t = 19.6 s

b) the friction force is

           fr = 0.65 2000 9.8

          fr = 1.274 10⁴ N

This is the braking force and also the forces that couple the cars.

3 0
3 years ago
The cycling of the air is a natural phenomenon as shown above is the result of
Ket [755]

Answer:

natural convection

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6 0
3 years ago
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A body starts from rest and travels 120cm in the 8th second.Find the<br> acceleration​
dlinn [17]

Answer:

Hey mate hope its help you....

4 0
3 years ago
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If a maserati. with a belocity of 6 m/s E, accelerates at a rate of 85 m/s^2 for 5 seconds, what will its velocity be?
Ksju [112]

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

<h3>How to calculate the final velocity a moving object?</h3>

From the first equation of equation of motion, final velocity is the sum of the initial velocity and the product of acceleration and time.

It is expressed as;

v = u + at

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

Given the data in the question;

  • Initial velocity u = 6m/s
  • Acceleration a = 85m/s²
  • Elapsed time t = 5s
  • Final velocity v = ?

Plug the given values into the first equation of motion and solve for v.

v = u + at

v = 6m/s + ( 85m/s² × 5s )

v = 6m/s + 425ms/s²

v = 6m/s + 425m/s

v = 431m/s

The final velocity of the Maserati after accelerating at the rate of 85 m/s² for 5 seconds is 431m/s.

Learn more about the first equation of equation here: brainly.com/question/20381052

#SPJ1

7 0
1 year ago
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