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Mars2501 [29]
2 years ago
11

Which compound has both covalent and ionic bonds? pls give the explanation thx :)

Chemistry
1 answer:
lana66690 [7]2 years ago
5 0

Answer:

B.) Na₂SO₄

Explanation:

Covalent bonds are bonds which involve electrons being shared between two atoms. These bonds only occur between nonmetals.

Ionic bonds are bonds which involve electrons being given or taken by two atoms. These bonds form between a metal and a nonmetal.

NH₃ contains nitrogen and hydrogen, two nonmetals. Therefore, this molecule only contains covalent bonds.

Na₂SO₄ has both covalent and ionic bonds. The covalent bonds are found within the polyatomic ion, SO₄²⁻. Sulfur and oxygen are both nonmetals, thus covalently combining. The ionic bond forms between the  Na⁺ and SO₄²⁻. Sodium (Na) is a metal which wishes to give up electrons to have a complete octet. SO₄²⁻ serves as the anion which it bonds with.

CH₃COOH contains hydrogen, carbon, and oxygen. All of these are nonmetals, thus the only bonds formed are covalent.

NaCl contains sodium, a metal, and chlorine, a nonmetal. Therefore, this compound is held together by an ionic bond.

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Answer:

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3 years ago
What is the name of the variable that you change in an expiernment
maksim [4K]
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3 years ago
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What is the volume of 7.50x10^24 molecules of NH3 at STP
Bas_tet [7]

Answer:

V NH3 = 304.334 L

Explanation:

  • 1 mol ≡ 6.02 E23 molecules

⇒ moles NH3 = (7.50 E24 molecules)×(mol/6.022 E23 molecules)

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assuming ideal gas:

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4 0
4 years ago
As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
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Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

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so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

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3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

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