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Mars2501 [29]
1 year ago
11

Which compound has both covalent and ionic bonds? pls give the explanation thx :)

Chemistry
1 answer:
lana66690 [7]1 year ago
5 0

Answer:

B.) Na₂SO₄

Explanation:

Covalent bonds are bonds which involve electrons being shared between two atoms. These bonds only occur between nonmetals.

Ionic bonds are bonds which involve electrons being given or taken by two atoms. These bonds form between a metal and a nonmetal.

NH₃ contains nitrogen and hydrogen, two nonmetals. Therefore, this molecule only contains covalent bonds.

Na₂SO₄ has both covalent and ionic bonds. The covalent bonds are found within the polyatomic ion, SO₄²⁻. Sulfur and oxygen are both nonmetals, thus covalently combining. The ionic bond forms between the  Na⁺ and SO₄²⁻. Sodium (Na) is a metal which wishes to give up electrons to have a complete octet. SO₄²⁻ serves as the anion which it bonds with.

CH₃COOH contains hydrogen, carbon, and oxygen. All of these are nonmetals, thus the only bonds formed are covalent.

NaCl contains sodium, a metal, and chlorine, a nonmetal. Therefore, this compound is held together by an ionic bond.

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zhuklara [117]

Answer:

Mg^{+2}

Explanation:

The oxidation state of S is (-2) and that of Mg is (+2) since Mg loses two electrons to S

5 0
3 years ago
What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas a
Alexandra [31]

144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

<h3>What is Ideal Gas Law ? </h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm  [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K  [At STP]

Now first find the number of moles

F₂  +  CaBr₂  →  CaF₂  +  Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So,  199.89 g CaBr₂ reacts with  = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}

n = 0.0064 mole

Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

Learn more about the Ideal Gas here: brainly.com/question/20348074

#SPJ4

4 0
1 year ago
What is abbreviated structural formula of the 2-metil-5-isopropiloctan?​
Alja [10]

Answer:

            CH3

            |

CH3-    C H  -CH2-CH2-      CH   - CH2-CH2-CH3

                                              |

                                              CH

                                           /     \

                                         CH3  CH3

Explanation:

Octan

C-C-C-C-C-C-C-C

Metyl

CH3 -

Isopropyl

     CH3

    /

- CH

   \

     CH3

2-metil-5-isopropiloctan

           CH3

            |

CH3-    C H  -CH2-CH2-      CH   - CH2-CH2-CH3

                                              |

                                              CH

                                           /     \

                                         CH3  CH3

                           

8 0
3 years ago
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Answer:

Explanation:

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