Its phosphorus (P)In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.
Answer:
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Explanation:
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Explanation:
The atomic theory is that all matter is made up of tiny units or particles called atoms. This theory describes the characteristics, structure and behavior of atoms as well as the components that make up atoms. Furthermore, the theory states that all elements are made up of identical atoms.
The atomic theory is a theory in the study of chemistry that states atoms are the building blocks of matter. Atoms contain protons, neutrons and electrons. Protons, which have a positive charge, and neutrons are found in the nucleus of the atom. Electrons, which have a negative charge, orbit the nucleus.
According to the atomic theory, all elements contain atoms. The difference is the number of protons, electrons and neutrons in that atom. For instance, hydrogen contains one proton and one electron but no neutrons. Oxygen, on the other hand contains eight protons, electrons and neutrons. The difference in protons, electrons and neutrons determines the stability and the other properties of any particular element. These elements are grouped according to their atomic masses, which depend on the number of protons and neutrons in each of the atoms. Because oxygen has more protons and neutrons than hydrogen, it has a higher atomic mass.
There are 19.5 g Na in 71.4 g NaHCO₃
Calculate the <em>molecular mass of NaHCO₃</em>.
1 Na = 1 × 22.99 u = 22.99 u
1 H = 1 × 1.008 u = 1.008 u
1 C = 1 × 12.01 u = 12.01 u
3 O = 3 × 16.00 u = <u>48.00 u
</u>
TOTAL = 84.008 u
So, there are 22.99 g of Na in 84.008 g NaHCO₃.
∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na
D) All three bulbs would go out because the circuit would no longer have a ground thereby deeming it "open".
