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3 years ago

Can someone please help me answer that question

Chemistry

1 answer:

Artyom0805 [142]3 years ago

3 0

Answer:

Mk but in just a minute I gotta go for a sec and do my homework.

Explanation:

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What do you predict will happen to the volume inside a container when pressure & temperature remains constant but the number

Pani-rosa [81]

Answer:

<u>increase</u>

Explanation:

<u>The Ideal Gas Equation</u>

PV = nRT
V = nRT/P
V ∝ n

The volume of a gas is directly proportional to the number of moles it contains. Hence, if the number of particles is increased, then the volume inside the container will <u>increase</u>

7 0

2 years ago

A silver block, initially at 57.2 ∘C, is submerged into 100.0 g of water at 24.8 ∘C, in an insulated container. The final temper

Masteriza [31]

Answer:

96.5 grams is the mass of the silver block.

Explanation:

Heat lost by iron will be equal to heat gained by the water

$-Q_1=Q_2$

Mass of iron = $m_1=?$

Specific heat capacity of silver= $c_1=0.240 J/g^oC$

Initial temperature of the silver= $T_1=120^oC$

Final temperature = $T_2=T=26.5^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=100.0 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=24.8 ^oC$

Final temperature of water = $T_2=T=26.5^oC$

$Q_2=m_2c_2\times (T-T_3)$

$-Q_1=Q_2$

$-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)$

On substituting all values:

$-(m_1\times 0.240 J/g^oC\times (26.5^oC-57.2^oC))=100.0 g\times 4.184 J/g^oC\times (26.5^oC-24.8^oC)$

we get, $m_1 = 96.5 g$

96.5 grams is the mass of the silver block.

5 0

3 years ago

If you dilute 40.0 mL of a 7.0 M solution to make 100.0 mL of solution, what is the molarity of the dilute solution?

Burka [1]

Answer:

2.8M

Explanation:

The following data were obtained from the question:

Volume of stock solution (V1) = 40mL

Molarity of the stock solution (M1) = 7M

Volume of diluted solution (V2) = 100mL

Molarity of diluted solution (M2) =?

Using the dilution formula, we can easily find the molarity of the diluted solution as follow:

M1V1 = M2V2

7 x 40 = M2 x 100

Divide both side by 100

M2 = (7 x 40)/100

M2 = 2.8M

Therefore, the molarity of the diluted solution is 2.8M

3 0

3 years ago

Two raw materials used in manufacturing of indenouse soap

Trava [24]

Answer:Naoh and animal fats

Explanation:

Also perfume along with ones desire

Feel pleasure to help u

8 0

3 years ago

Calculate the pH of a buffer solution when 32.0 mL of a 0.25 M H2CO3 is mixed with 20.0 mL of a 0.15 M NaHCO3

ikadub [295]

pH of buffer solution : 4.32

<h3>Further explanation </h3>

A buffer solution is a solution that can maintain a good pH value due to the addition of a little acid or a little base or dilution.

The buffer solution can be acidic or basic

Acid buffer solutions consist of weak acids(H₂CO₃) and their salts.(NaHCO₃)

mol H₂CO₃

$\tt 0.032\times 0.25=0.008$

mol NaHCO₃

$\tt 0.02\times 0.15=0.003$

$\tt [H^+]=Ka\dfrac{mole~weak~acid}{mole~salt}\\\\(H^+]=1.8\times 10^{-5}\dfrac{0.008}{0.003}=4.8\times 10^{-5}\\\\pH=5-log~4.8=4.32$

5 0

3 years ago