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dimaraw [331]
4 years ago
5

Predict which atom has a higher ionization energy. CL or I

Chemistry
2 answers:
maw [93]4 years ago
8 0

Answer:

The answer is chlorine (Cl)

Explanation:

Ionization energy is the minimum amount of energy required to remove a valence electron from an atom in its gaseous state. The closer the valence electron (negatively charged) is to the nucleus (positively charged), the higher the ionization energy required to remove it, hence ionization energy generally decreases down the group.

Between the two, chlorine comes first in the group before iodine and hence has a higher ionization energy (as explained earlier) than Iodine

bija089 [108]4 years ago
7 0
I'm pretty sure your answer is CL.
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The intensity of illumination at any point from a light source is proportional to the square of the reciprocal of the distance b
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Answer:

the stronger light 5.5 m apart from the total illumination​

Explanation:

From the problem's statement , the following equation can be deducted:

I= k/r²

where I = intensity of illumination , r= distance between the point and the light source , k = constant of proportionality

denoting 1 as the stronger light and 2 as the weaker light

I₁= k/r₁²

I₂= k/r₂²

dividing both equations

I₂/I₁ = r₁²/r₂²=(r₁/r₂)²

solving for r₁

r₁ = r₂ * √(I₂/I₁)

since we are on the line between the two light​ sources , the distance from the light source to the weaker light is he distance from the light source to the stronger light + distance between the lights . Thus

r₂ = r₁ + d

then

r₁ = (r₁ + d)* √(I₂/I₁)

r₁ = r₁*√(I₂/I₁) + d*√(I₂/I₁)

r₁*(1-√(I₂/I₁)) =  d*√(I₂/I₁)

r₁ = d*√(I₂/I₁)/(1-√(I₂/I₁))  =

r₁ = d/[√(I₁/I₂)-1)]

since the stronger light is 9 times more intense than the weaker

I₁= 9*I₂ → I₁/I₂ = 9 →√(I₁/I₂)= 3

then since d=11 m

r₁ = d/[√(I₁/I₂)-1)] = 11 m / (3-1) = 5.5 m

r₁ = 5.5 m

therefore the stronger light 5.5 m apart from the total illumination​

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3 years ago
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Explanation:

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The energy should be measured in Joules i.e J

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