Using the atomic weights, K = 39, O=16 so KO2= 39+32=71. So K=39/71= 0.549 of KO2 and O2=32=0.45KO2 and O2=8g and 0.45KO2=8g so KO2=8/0.45=17.77g. So to check, K=0.549 x 17.77g=9.76 and so K+O2= 9.76+8g=17.76.
Molar mass Argon ( Ar ) = 39.95 g/mol
39.95 g ---------------- 6.02 x 10²³ atoms
0.377 g ---------------- ( atoms Ar )
( atoms Ar ) = 0.377 x ( 6.02 x 10²³ ) / 39.95
( atoms Ar ) = 2.26954 x 10²³ / 39.95
= 5.68 x 10²¹ atoms Ar
hope this helps!
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thats just the answer i have no more to say
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