Answer: look at the close because that is the answer
Explanation:
Answer is: (4) proton and neutron.
One unified atomic mass unit is approximately the mass of one nucleon (proton or neutron).
The unified atomic mass unit (amu) is a standard unit of atom mass.
One unified atomic mass unit is approximately the mass of one nucleon (1.66·10⁻²⁷ kg).
For example, one carbon atom has mass of 12 amu (unified atomic mass).
The electron has a mass that is approximately 1/1836 that of the proton.
Answer:
1.44 g
Explanation:
From the question given above, the following data were obtained:
Number of mole of HCl = 0.06 mole
Mass of Mg =?
From the question given above, we discovered the number of mole of HCl is equivalent to the number of mole of Mg. Thus,
Number of mole of Mg = number of mole of HCl
Number of mole of Mg = 0.06 mole
Finally, we shall determine the mass of Mg. This can be obtained as follow:
Number of mole of Mg = 0.06 mole
Molar mass of Mg = 24 g/mol
Mass of Mg =?
Mass = mole × molar mass
Mass of Mg = 0.06 × 24
Mass of Mg = 1.44 g
Therefore, the mass of magnesium is 1.44 g
Answer:
a. Sn or Si ⇒ Sn
b. Br or Ga ⇒ Ga
c. Sn or Bi ⇒ similar in size
d. Se or Sn ⇒ Sn
Explanation:
The larger atom has a larger atomic radius. We have to consider how varies the atomic radius for chemical elements in the Periodic Table. In a group (column), the atomic radius increases from top to bottom while in a period (file), it increases from right to left.
a. Sn or Si ⇒ Sn
They are in the <u>same group</u>. Sn is on the top, so it has a larger atomic radius.
b. Br or Ga ⇒ Ga
They are in the <u>same period</u>. Ga is located at the left so it has a larger atomic radius.
c. Sn or Bi ⇒ similar
They are not in the same group neither the same period. Bi is located more at the bottom, so it would be larger than Sn, but Bi is also at the right side, so it would be smaller than Bi. Thus, they have comparable sizes.
d. Se or Sn⇒ Sn
They are not in the same group neither the same period. Se is located at the top and right side compared to Sn, so Sn is the larger atom.
Answer:
Explanation:
In the absence of external forces
Δ
→
p
=
0
so
m
b
1
→
v
b
1
+
m
b
2
→
v
b
2
=
m
a
1
→
v
a
1
+
m
a
2
→
v
a
2
Here we have
m
b
1
=
1000
,
→
v
b
1
=
25
ˆ
i
m
b
2
=
2000
,
→
v
b
2
=
15
ˆ
j
m
a
1
=
1000
,
→
v
a
1
=
→
v
a
m
a
2
=
2000
,
→
v
a
2
=
→
v
a
so
1000
⋅
25
ˆ
i
+
2000
⋅
15
ˆ
j
=
(
1000
+
2000
)
→
v
a
so
→
v
a
=
(
25
3
ˆ
i
+
10
ˆ
j
)
with
∣
∣
→
v
a
∣
∣
=
5
√
61
3
=
13.02
∠
→
v
a
=
arctan
(
10
/
(
25
3
)
)
=
50.2
∘
Kinetic energy before
K
b
=
1
2
m
b
1
∣
∣
→
v
b
1
∣
∣
2
+
1
2
m
b
2
∣
∣
→
v
b
2
∣
∣
2
Kinetic energy after
1
2
(
m
b
1
+
m
b
2
)
∣
∣
→
v
a
∣
∣
2
so
Δ
K
=
K
a
−
K
b
=
−
283333
.
[J]