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snow_tiger [21]
3 years ago
13

The visible spectrum of the Cr(acac)3

Chemistry
1 answer:
Sati [7]3 years ago
3 0

Explanation:

The observable visible spectrum of Cr(acac)3 complex is different from that of

[Cr(en)3]Br3 due to strength of bonded ligand in the coordination sphere.

en is a strong field ligand compared to acac thus pairing  occurs. In both the complexes

Cr is in +3 state, configuration [Ar] 3d^3. There are 3 unpaired e in Cr(acac)3 whereas 1 unpaired e in [Cr(en)3]Br3 due to pairing.

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42700 milliliters would be the answer...

Hope this helps!
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Light comes from A. Nerve impulses. B. Electrons. C. An object vibrating. D. Photons
Radda [10]
D. photons it contains light but with zero mass
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What are the products of the neutralization reaction between HCl and
liraira [26]

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opinion b

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4 0
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How many grams are in 2 moles of Iodine?
Nady [450]

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Explanation:

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6 0
3 years ago
Read 2 more answers
How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.
Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=200 K

Putting value in the given equation:

\frac{nRT}{P} =V

V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}

V= 1.1214 mL

Learn more about the ideal gas here:

brainly.com/question/27691721

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4 0
2 years ago
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