The total energy of the system remains the same.
Answer:
4f E₄ = 0.85 eV, L₄ = 4.22 10⁻³⁴
,
5d E₅ = 0.544 eV
, L5 = 5.28 10⁻³⁴
Explanation:
Let's use the Bohr model, stable the energy of the hydrogen atom
E = -13.606 / n2
where Eo = 13.606 eV is the energy of the ground states.
a) the energy of each atom
level 4f
In this nomenclature enumeration is the number n
E = -13606 / 42
E₄ = 0.85 eV
level 5d
E₅ = -13.606 / 5 2
E₅ = 0.544 eV
b) The angular momentum is given in Boh's model
L = n h / 2pi
let's calculate
level 4f L₄ = 4 6.63 10⁻³⁴-34 / 2 pi
L₄ = 4.22 10⁻³⁴
level 4d
L5 = 5 6.63 10-⁻³⁴ / 2pi
L5 = 5.28 10⁻³⁴
c) The hydrogen atom in state n = 5 has lower energy than the other state
d) Atom 1 has less angular momentum than atom 2
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Answer:
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