Molality= mol/ Kg
if we assume that we have 1 kg of water, we have 3.19 moles of solute.
the formula for mole fraction --> mole fraction= mol of solule/ mol of solution
1) if we have 1 kg of water which is same as 1000 grams of water.
2) we need to convert grams to moles using the molar mass of water
molar mass of H₂O= (2 x 1.01) + 16.0 = 18.02 g/mol
1000 g (1 mol/ 18.02 grams)= 55.5 mol
3) mole of solution= 55.5 moles + 3.19 moles= 58.7 moles of solution
4) mole fraction= 3.19 / 58.7= 0.0543
An allylic carbocation is a reactive intermediate in the reaction of 1,3-diene with her, resulting in 1,4-addition.
<h3>What is
carbocation?</h3>
- A molecule called a carbocation has three bonds and a positively charged carbon atom.
- They are essentially carbon cations, to put it simply.
- It was once referred to as carbonium ion.
- Any even-electron cation with a sizable positive charge on the carbon atom is now referred to as a carbocation.
<h3>Why are carbohydrate molecules crucial?</h3>
- Because charge can be exchanged between many atoms when the vacant p orbital of a carbocation overlaps with the p orbitals of another carbon-carbon double or triple bond, carbocations next to other carbon-carbon double or triple bonds are very stable.
Learn more about carbocation here:
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Answer:
Making models
Explanation:
Classifying is the grouping together of items that are alike in some way. Answer: Making models involves creating rep- resentations of complex objects or processes.
Answer:
0.441 L
Explanation:
At constant pressure, Using Charle's law :-
Given ,
V₁ = 0.500 L
V₂ = ?
T₁ = 25.0 °C
T₂ = -10.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (25 + 273.15) K = 298.15 K
T₂ = (-10 + 273.15) K = 263.15 K
Using above equation as:
<u>New volume = 0.441 L</u>
Answer:
1.40 atm is the pressure for the gas
Explanation:
An easy problem to solve with the Ideal Gases Law:
P . V = n . R .T
T° = 370K
V = 17.3L
n = 0.8 mol
Let's replace data → P . 17.3L = 0.8mol . 0.082L.atm/mol.K . 370K
P = (0.8mol . 0.082L.atm/mol.K . 370K) / 17.3L = 1.40 atm
