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romanna [79]
2 years ago
7

Which best describes the oxidizing agent in this reaction?

Chemistry
1 answer:
MissTica2 years ago
8 0

For the reaction Cl₂(aq) + 2 Br⁻(aq) ⇒ 2Cl⁻(aq) + Br₂(aq), Chlorine (Cl) is the oxidizing agent because it gains an electron.

<h3>What is the oxidizing agent?</h3>

In a redox reaction, the oxidizing agent is the one that gains electrons, causing the other element to oxidize.

Let's consider the following redox reaction.

Cl₂(aq) + 2 Br⁻(aq) ⇒ 2Cl⁻(aq) + Br₂(aq)

The corresponding half-reactions are:

Reduction: 2 e- + Cl₂(aq) ⇒ 2Cl⁻(aq)

Oxidation: 2 Br⁻(aq) ⇒ Br₂(aq) + 2 e-

Which best describes the oxidizing agent in this reaction?

  • Bromine (Br) is the oxidizing agent because it gains an electron. NO. Br is the reducing agent.
  • Bromine (Br) is the oxidizing agent because it loses an electron. NO. Br is the reducing agent.
  • Chlorine (Cl) is the oxidizing agent because it gains an electron. YES.
  • Chlorine (Cl) is the oxidizing agent because it loses an electron. NO. Cl gains electrons.

For the reaction Cl₂(aq) + 2 Br⁻(aq) ⇒ 2Cl⁻(aq) + Br₂(aq), Chlorine (Cl) is the oxidizing agent because it gains an electron.

Learn more about oxidizing agents here: brainly.com/question/9064518

#SPJ1

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4 years ago
Quinine (C20H24N2O2) is the most important alkaloid derived from cinchona bark. It is used as an antimalarial drug. For quinine
dolphi86 [110]

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The pH of saturated solution of the quinine is 10.05

Explanation:

Quinine (Q) is C20H24N2O2 has a molar mass of 324.4 g/mol

Q can behave as a weak base. Kb and pKb can be calculated for weak bases

pKb1 is to be considered when solving the question.

pKb1 = 5.1

Step 1 : Calculate the Kb of Quinine

            pKb1 = - log [kb]

                5.1  = - log [kb]

                take Antilog of both side

             [kb] = 7.94 x 10∧-6

Step 2: Calculate the concentration of saturated solution of Q in mol/dm3

           From the question, 1900 ml of solution contains 1 g of Q

           Therefore,  1000 ml of solution will contain........... x g of Q

           x = 1000 /1900

           x = 0.526 g in 1 dm3

In calculating concentration in mol/dm3,

Concentration in mol/dm3 = concentration in g /dm3 divided by molar mass

Molar mass of Q = 324.4

Concentration in mol/dm = 0.526 /324.4

                                         = 0.0016 mol/dm3

Step 3: Calculating the Concentration of OH-

            At Equilibrium, Kb = x² / 0.0016

            7.94 x 10∧-6 = x² / 0.0016

            x = √ 0.0016 × 7.94 x 10∧-6

            x = 1. 127 × 10∧-4 mol/dm3

The concentration of OH- = 1. 127 × 10∧-4 mol/dm

Step 4:  Calculating the pH of Quinine

           Recall, pOH = - log [OH-]

           pOH = - log [1. 127 × 10∧-4]

           pOH = 3.948

           Also recall that pH + pOH = 14

           pH = 14 - 3.948

           pH = 10.05

           

8 0
4 years ago
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