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Tanya [424]
1 year ago
7

Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium woul

d still be radioactive two months later?
Chemistry
1 answer:
nalin [4]1 year ago
3 0

Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

A = A_{0} \times (\frac{1}{2})^{t/T}

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t  = 2 months = 60 days

T = 11.6 days  

Now put the values in above expression we get

A = A_{0} \times (\frac{1}{2})^{t/T}

   = 0.50 \times (\frac{1}{2})^{60/11.6}

   = 0.50 \times (\frac{1}{2})^{5.17}

   = 0.50 × 0.0277

   = 0.0138 g

   = 13.8 mg          [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

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crimeas [40]
The correct answer is that organic compounds get their name from its association with living organisms. The word "organic" means living. That's how they are related and that's how organic compounds get their name. I hope this answer helped you. 
4 0
3 years ago
A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day give
bixtya [17]

The amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

<h3>What is the amount of Amoxicillin dose given to the child?</h3>

The amount of  Amoxicillin  dose given to the child is calculated as follows;

amount of Amoxicillin dose = weight of the child x dosage prescribed

<h3>What is the weight of the child in pounds (lb) </h3>

The weight of the child in pounds (lb) is calculated as follows;

1 lb = 0.453592 kg

85.4 lb = ?

= 85.4 x 0.453592 kg

= 38.74 kg

amount of Amoxicillin dose = 38.74 kg x 45 mg/kg

amount of Amoxicillin dose = 1,743.3 mg

Thus, the amount of Amoxicillin dose given to the 85.4 lb child daily is determined as 1,743.3 mg.

Learn more about amount of dose here: brainly.com/question/11185154

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The complete question is below:

A 85.4 lb child has a Streptococcus infection. Amoxicillin is prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d. Calculate the daily dose of the child.

7 0
1 year ago
Help please asap. chem sucks
luda_lava [24]

I'm assuming that C is carbon.

4.590 \: mol \: c \times  \frac{12.01 \:g \: c}{1 \: mol \: c}

55.1259 g of C

6 0
2 years ago
why do we heat the test tube in a glass beaker during a chemistry experiment and not directly over a flame?
bearhunter [10]
It is not directly over a flame because it depends on the substance you might not want to heat it too much.you never know what could happen
7 0
3 years ago
Use IUPAC rules to name this compound. A) nitrogen iodide B) nitrogen triiodide C) mononitrogen iodide D) mononitrogen triiodide
Mariulka [41]

Answer:

Name of the compound is Nitrogen triiodide.

Explanation:

According to the IUPAC rules, to naming of the compound the following formula can be applied.

Prefix + Name of first element + Base name element of second element + Suffix.

The given compound - NI_{3}

Name of first element- Nitrogen

Base name element of second element - Iodine

Suffix = 3 = tri

Here, iodine is in ionic form therefore, it becomes iodide. and then suffix will be added in front of the halogen.

Therefore, name of the compound will be  Nitrogen triiodide..

3 0
3 years ago
Read 2 more answers
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