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stira [4]
3 years ago
7

Kim described two subatomic particles below:

Chemistry
2 answers:
SashulF [63]3 years ago
4 0

Answer:

Was it right

Explanation:

Airida [17]3 years ago
3 0
I agree with him I also think it is #2 but it's hard to explain, it just makes more sence...
hope this helps!
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Write the following measurement out of scientific notation. 2.345 x 10^-4 cm.
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When salt is mixed in water, what is the salt and water? A)salt is the solution, water is the solute. B)salt is the solvent, wat
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Answer:

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Explanation:

C) salt is the solute, water is the solvent.

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An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?
umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_{solute} = Given mass of solute (CsCl) = 8.00 g

M_{solute} = Molar mass of solute (CsCl) = 168.4  g/mol

W_{solvent} = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

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3 years ago
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Alona [7]
The equation presented above is that of uranium reacting with fluorine forming uranium fluoride. 

The chemical reaction can be balanced by carefully studying the equation and balancing the number of atoms of each of the element in both sides of the chemical reaction. That is,
 
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3 years ago
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