Question

A 58.5 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 41.7 kg boy stands at one end of the board. He walks from one end of the board to the other end with a velocity of 1.27 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice?

Answer 1

The velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s

• What is conservation of momentum:

It states the amount of momentum remains constant

Momentum of a moving body is the product of mass times velocity.

Formula for momentum:

• P = m* v

When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

here,

mass of wood, m=58.5 kg

mass of boy, M=41.7 kg

velocity of the boy V=1.27 m/s

Thus,

The conservation of momentum,

m*v = M*V

substituting the value,

(58.5*v) = 1.27* 41.7

v = 52.95 / 58.5

v = 0.905 m/s

Thus, the velocity of the wood board which is resting on very smooth ice in the middle of a frozen lake relative to this ice is 0.905 m/s.

Learn more about the conservation of momentum here;

brainly.com/question/3920210

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