Answer:
Explanation:
Ultrasonic waves are acoustic waves that are so high in frequency that humans can't hear them; however, infrasonic waves are sound waves that are lower in frequency than what humans can hear. A subsonic wave is a wave that is traveling slower than the speed of sound and a supersonic waves travels faster
If your ref points are each other and not the surrounding environment, at the same speed you would both appear to be stationary
Answer:
the final potential energy of this system is 3U0/10
Explanation:
We are given
charge at left end and another test charge at point p
Potential energy is given by =
where k is electrostatics constant =
Q1 = first charge , Q2= test charge
R= distance between charges
potential at point p
U0 = k*Q1*Q2 /3 ⇒ kq1q2 = 3U0 ..............1
now the test charge moves to point R
using Pytahgoreou theorem
R(distance) = = 10
New Potential energy
U1 = kq1*q2 / 10
substituting kq1q2 = 3U0 from 1
U1 = 3U0/10
So this is the final potential energy of this system.
Answer:
A) F_g = 4.05 10⁻⁴⁷ N, B) F_e = 9.2 10⁻⁸N, C) = 2.3 10³⁹
Explanation:
A) It is asked to find the force of attraction due to the masses of the particles
Let's use the law of universal attraction
F =
let's calculate
F =
F_g = 4.05 10⁻⁴⁷ N
B) in this part it is asked to calculate the electric force
Let's use Coulomb's law
F =
let's calculate
F =
F_e = 9.2 10⁻⁸N
C) It is asked to find the relationship between these forces
= 2.3 10³⁹
therefore the electric force is much greater than the gravitational force
Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
a E =
b E =
c E = 0 N/C
d
e
f V =
g
h
i
Explanation:
From the question we are given that
The first charge
The second charge
The first radius
The second radius
And
The objective is to obtain the the magnitude of electric for different cases
And the potential difference for other cases
Considering a
r = 4.00 m
Considering b
This implies that the electric field would be
This because it the electric filed of the charge which is below it in distance that it would feel
=
Considering c
r = 0.200 m
=>
The electric field = 0
This is because the both charge are above it in terms of distance so it wont feel the effect of their electric field
Considering d
r = 4.00 m
=>
Now the potential difference is
This so because the distance between the charge we are considering is further than the two charges given
Considering e
r = 1.00 m
Considering f
Considering g
Considering h
Considering i