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liberstina [14]
2 years ago
12

Why is cellular respiration essential for homeostasis? (4 points)

Physics
2 answers:
BARSIC [14]2 years ago
8 0
1Cellular respiration supports homeostasis to maintain the stability of body. ATP is produced during cellular respiration that provides energy to perform several body functions such as muscle contraction and nerve conduction which are responsible for the maintenance of homeostasis
2. The only form of energy a cell can use is a molecule called adenosine triphosphate (ATP). Chemical energy is stored in the bonds that hold the molecule together. ADP can be recycled into ATP when more energy becomes available
3. The lungs and respiratory system allow us to breathe. They bring oxygen into our bodies (called inspiration, or inhalation) and send carbon dioxide out (called expiration, or exhalation). This exchange of oxygen and carbon dioxide is called respiration.
4. The regulation of tissue oxygenation is based at the start from the ability of the respiratory system to fully oxygenate the arterial blood which the heart then delivers to the peripheral tissues. The need for different levels of respiration varies with the physiologic state of the organism (e.g., sleep, excitement, exercise). The respiratory system must try to maintain constant levels of O2, CO2 and H+ in the arterial blood which then ensures relatively constant levels of these important substances in the interstitial fluid. For O2, one needs an adequate supply to meet cellular metabolic requirements. For CO2 and H+, one needs to maintain the acid–base status of the body's cells
5. New cells are created from a process called cell division. The new cells are produced when a cell, called the mother cell, divides into new cells called daughter cells. When two daughter cells have the same number of chromosomes as the original cell, the process is called mitosis
Anastaziya [24]2 years ago
6 0
To create energy that the cell can use hope this helped x
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Answer:

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Answer:

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If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
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Answer:

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

K.E = eV--------------- equation (1)

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e = charge on electron = 1.6 x 10⁻¹⁹ C

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The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

\\\frac{1}{2}mv^{2} = eV\\\\\frac{1}{2}(9.1\ x\ 10^{-31}\ kg)v^{2} = (1.6\ x\ 10^{-19}\ C)(9900\ volts)\\\\v = \sqrt{34.81\ x\ 10^{14}} \\

<u>v = 5.9 x 10⁷ m/s</u>

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