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liberstina [14]
2 years ago
12

Why is cellular respiration essential for homeostasis? (4 points)

Physics
2 answers:
BARSIC [14]2 years ago
8 0
1Cellular respiration supports homeostasis to maintain the stability of body. ATP is produced during cellular respiration that provides energy to perform several body functions such as muscle contraction and nerve conduction which are responsible for the maintenance of homeostasis
2. The only form of energy a cell can use is a molecule called adenosine triphosphate (ATP). Chemical energy is stored in the bonds that hold the molecule together. ADP can be recycled into ATP when more energy becomes available
3. The lungs and respiratory system allow us to breathe. They bring oxygen into our bodies (called inspiration, or inhalation) and send carbon dioxide out (called expiration, or exhalation). This exchange of oxygen and carbon dioxide is called respiration.
4. The regulation of tissue oxygenation is based at the start from the ability of the respiratory system to fully oxygenate the arterial blood which the heart then delivers to the peripheral tissues. The need for different levels of respiration varies with the physiologic state of the organism (e.g., sleep, excitement, exercise). The respiratory system must try to maintain constant levels of O2, CO2 and H+ in the arterial blood which then ensures relatively constant levels of these important substances in the interstitial fluid. For O2, one needs an adequate supply to meet cellular metabolic requirements. For CO2 and H+, one needs to maintain the acid–base status of the body's cells
5. New cells are created from a process called cell division. The new cells are produced when a cell, called the mother cell, divides into new cells called daughter cells. When two daughter cells have the same number of chromosomes as the original cell, the process is called mitosis
Anastaziya [24]2 years ago
6 0
To create energy that the cell can use hope this helped x
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A hiker, caught in a rainstorm might absorb 1 liter of water in her clothing. if it is windy so that this amount of water is eva
NeTakaya

Water evaporates at 100⁰C

So change in temperature = 100-20 = 80⁰C

Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg

Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg

So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ

So amount of heat require to evaporate water = 334.88 kJ

4 0
3 years ago
E<br> 3.6 What force is needed to give a mass of<br> 20 kg an acceleration of 5 m/s??
luda_lava [24]

Explanation:

  • Mass(m)= 20kg
  • Acceleration (a)= 5m/s²
  • Force(F)= ?

We know that,

  • F=ma
  • F=20×5
  • F=100N

Hence, the needed force is 100N.

6 0
1 year ago
Read 2 more answers
you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k
alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}

→ v_{p}=150 km/h ,  v_{w}=50 km/h

→ v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11 km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is tan^{-1}\frac{50}{150}=18.4°

The direction of the velocity is 18.4° west of south

<em>You should choose airspeed 158.11 km/h at 18.4° west of south</em>

8 0
3 years ago
The maximum oxygen uptake is known as the
grandymaker [24]
<span>The maximum oxygen uptake is known as the VO max.</span>
3 0
3 years ago
An object whose specific gravity is 0.850 is placed in water. What fraction of the object is below the surface of the water?
Fynjy0 [20]

Answer:

The fraction of the object that is below the surface of the water is ¹⁷/₂₀

Explanation:

Given;

specific gravity of the object, γ = 0.850

Specific gravity is given as;

specific \ gravity = \frac{density \ of the \ object}{density \ of \ water}\\\\0.85= \frac{density \ of the \ object}{1000 \ kg/m^3} \\\\density \ of the \ object = 850 \ kg/m^3

Fraction of the object's weight below the surface of water is calculated as;

= \frac{850}{1000} \ \times\ 100\%\\\\= 85 \% \\\\= \frac{17}{20}

Therefore, the fraction of the object that is below the surface of the water is ¹⁷/₂₀

8 0
3 years ago
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