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liberstina [14]
3 years ago
12

Why is cellular respiration essential for homeostasis? (4 points)

Physics
2 answers:
BARSIC [14]3 years ago
8 0
1Cellular respiration supports homeostasis to maintain the stability of body. ATP is produced during cellular respiration that provides energy to perform several body functions such as muscle contraction and nerve conduction which are responsible for the maintenance of homeostasis
2. The only form of energy a cell can use is a molecule called adenosine triphosphate (ATP). Chemical energy is stored in the bonds that hold the molecule together. ADP can be recycled into ATP when more energy becomes available
3. The lungs and respiratory system allow us to breathe. They bring oxygen into our bodies (called inspiration, or inhalation) and send carbon dioxide out (called expiration, or exhalation). This exchange of oxygen and carbon dioxide is called respiration.
4. The regulation of tissue oxygenation is based at the start from the ability of the respiratory system to fully oxygenate the arterial blood which the heart then delivers to the peripheral tissues. The need for different levels of respiration varies with the physiologic state of the organism (e.g., sleep, excitement, exercise). The respiratory system must try to maintain constant levels of O2, CO2 and H+ in the arterial blood which then ensures relatively constant levels of these important substances in the interstitial fluid. For O2, one needs an adequate supply to meet cellular metabolic requirements. For CO2 and H+, one needs to maintain the acid–base status of the body's cells
5. New cells are created from a process called cell division. The new cells are produced when a cell, called the mother cell, divides into new cells called daughter cells. When two daughter cells have the same number of chromosomes as the original cell, the process is called mitosis
Anastaziya [24]3 years ago
6 0
To create energy that the cell can use hope this helped x
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A rock is dropped off a cliff and falls the first half of the distance to the ground in t1 seconds. If it falls the second half
Hitman42 [59]

Answer:

t2/t1 = \sqrt{2} - 1

Explanation:

The expression for the second law of motion is given below:

h = ut + 0.5at^2

<u>For first half distance</u>

Object is initially at rest, so its initial speed u = 0

Object falls at half the distance, so h = h/2 where t = t1

Hence, we have

h/2 = at1^2/2 - equation 1

<u>For second half distance: </u>

Similarly,

h = a(t1 + t2)^2/2 - equation 2 where t = t1 + t2 and u= 0

Using equation 2 by equation 1

we obtain 2 = (t1 + t2)^2/t1^2

Hence t2/t1 + 1 = \sqrt{2}

Hence t2/t1 = \sqrt{2} - 1

5 0
3 years ago
Which energy transformation occurs when you light a gas burner?​
Eddi Din [679]

Answer:

Chemical energy to thermal(heat) energy

Explanation:

A gas burner contains chemical hydrocarbon such as methane, this methane is highly flammable.

The gas burner which contains methane when lighted up converts the chemical energy in the chemical to heat energy through the fire it produces. The fire then helps in heating up the surface it is applied to.

3 0
3 years ago
The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.
grin007 [14]
<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

The speed of light in a transparent medium is 0.6 times that of its speed in vacuum .

Refractive index of medium = speed of light in vacuum / speed of light in medium  

So

RI = 1/0.6 = 5/3 or 1.66

3 0
3 years ago
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Is the box moving at a constant speed? Explain how you know. What does this tell you about the kinetic energy of the system
mars1129 [50]

Answer:

The box is moved at constant speed, then the change in kinetic energy is zero.

Explanation:

Let suppose that box moves at constant speed, meaning that its kinetic energy (K), measured in joules, is expressed by the following equation:

K = \frac{1}{2}\cdot m\cdot v^{2} (1)

Where:

m - Mass, measured in kilograms.

v - Speed, measured in meters per second.

If the box moves at constant speed, then we notice that v_{f}^{2}-v_{o}^{2} = 0, therefore, \Delta K = 0. In a nutshell, if the box is moved at constant speed, then the change in kinetic energy is zero.

8 0
3 years ago
The acceleration of the body in the graph given below is____
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