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Mumz [18]
3 years ago
9

You want to determine whether the race of the defendant has an impact on jury verdicts. You assign participants to watch a trial

with either a Hispanic or Caucasian defendant, and you measure on a 1 (not at all) to 7 (very) scale how confident they feel the defendant is guilty. This is a confidence scale represents a _________ scale of measurement
Engineering
1 answer:
Andru [333]3 years ago
6 0

Answer:

The confidence scale represents an ordinal scale of measurement

Explanation:

An ordinal scale or level of measurement is used to measure attributes that can be ranked or ordered, but the interval between the attributes do not have quantitative significance. In this case, the measurement was done on a scale of 1 - 7, with a "1" being; not all that race of defendant has an impact on jury verdicts and a "7" being "very" meaning that race indeed has impact on jury verdicts. Another example can be a survey carried out on the level of customer satisfaction on a particular product, with "1" most dissatisfied and "10 " representing most satisfied. In the first example, it is wrong to say that the difference between 1 being "not at all" and maybe 3 is the same as the difference between 5 and 7 which have different connotations, because the numbers are merely for tagging and not to quantify.

Other levels of measurement include:

1. Nominal: this is the simplest level of measurement and it is simply used to categorize the attributes. Example is taking a survey on gender in the categories of male, female and transgender.

2. Interval: the interval scale is used when the distance between two attributes have meanings but there is no true zero value associated with the scale.

3. Ratio: this combines all the other three levels of measurement and is used to categorize, used to show ranking, has meaningful distances between the attributes and the scale has a true zero point. Example is the measurement of temperature using the celcius scale thermometer, where there is a true zero point at 0°C and the distance between 5°C and 10°C is the same as the distance between 10°C and 15°C.

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1. Examine the following circuit. Find RT, I3, R1, R2, R3, V1, V2 and V3. Show all of your work clearly below.
Mkey [24]

Explanation:

Ohm's law is used here. V = IR, and variations. The voltage across all elements is the same in this parallel circuit. (V1 =V2 =V3)

The total supply current is the sum of the currents in each of the branches. (It = I1 +I2 +I3)

Rt = (8 V)/(8 A) = 1 Ω . . . . supply voltage divided by supply current

I3 = 8A -3A -4A = 1 A . . . . supply current not flowing through other branches

R1 = (8 V)/(3 A) = 8/3 Ω

R2 = (8 V)/(4 A) = 2 Ω

R3 = (8 V)/(I3) = (8 V)/(1 A) = 8 Ω

V1 = V2 = V3 = 8 V

6 0
3 years ago
PELASEE HELPPP WITH MARK BRAINLIST!!!! You are stopped at a red light, and a long string of cars is crossing in front of you. Wh
choli [55]

Answer:

1st one.

Explanation:

I think that because they the one who is going to get a ticket and also you will not gonna get in a car accident.

7 0
3 years ago
Read 2 more answers
4) A steel tape is placed around the earth at the equator when the temperature is 0 C. What will the clearance between the tape
snow_lady [41]

Answer:

2102.1 m

Explanation:

Temperature at the equator = 0⁰

Radius of the earth = 6.37x10⁶

Required:

We how to find out what the clearance between tape and ground would be if temperature increases to 30 degrees.

Final temperature = ∆T = 303-273 = 30

S = 11x10^-6

The clearance R = Ro*S*∆T

=6.37x10⁶x 11x10^-6x30

= 2102.1m

Or 2.102 kilometers

Thank you

4 0
3 years ago
A dice is thrown 420 times and the number 6 is obtained 63 times; express the frequency of obtaining
STatiana [176]

Answer: 15%

Explanation:

Frequency of obtaining = 63/420 = 0.15 = 15%

6 0
2 years ago
Problem 9.11 A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain f
BabaBlast [244]

Answer:

the critical flaw length is 10.06 mm

Explanation:

Given the data in the question;

plane strain fracture toughness K_{tc = 92 Mpa√m

yield strength σ_y = 900 Mpa

design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa

Y = 1.15

we know that;

Critical crack length a_c = 1/π( K_{tc / Yσ )²

we substitute

a_c = 1/π( 92 Mpa√m / (1.15 × 450 Mpa  )²

a_c = 1/π( 92 Mpa√m / (517.5 Mpa  )²

a_c = 1/π( 0.177777  )²

a_c = 1/π( 0.03160466 )

a_c = 0.01006 m = 10.06 mm

Therefore, the critical flaw length is 10.06 mm

{ a_c = ( 10.06 mm ) > 3 mm

The critical flow is subject to detection

5 0
3 years ago
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