Answer:
Explanation:
A )
Magnetic field due to a long wire
B = (μ₀ / 4 π ) x( 2i / r )
= 10⁻⁷ x 2 i / r
where i is current , r is distance of point from the wire
Magnetic field at a point in between the wire will be total of magnetic field generated by both the wires
= 10⁻⁷ [ ( 2 x 2.2 / .009 - 2 x 2.2 / .009 ) ]
= 0
The magnetic field acts in opposite direction so they cancel out each other .
B )
At this point their magnetic field will add up
Net magnetic field
= 10⁻⁷ [ ( 2 x 2.2 / .018 + 2 x 2.2 / .036 ) ]
= 10⁻⁷ [ ( 244.44 + 122.22 ) ]
= 10⁻⁷ x 366.66
= 366.66 x 10⁻⁷ T .
C ) Force on a wire in a magnetic field = BiL where B is magnetic field , i is current and L is length of the wire . If length is one then
force = Bi
magnetic field on each wire
= B = (μ₀ / 4 π ) x( 2i / r )
= 10⁻⁷ x 2 x 2.2 / .018
= 244.44 x 10⁻⁷ T
force on each per unit length
= Bi
= 244.44 x 10⁻⁷ x 2.2
= 537.77 x 10⁻⁷ N /m
This is force of interaction between the two wires . Since direction of current is same , they will attract each other .
