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3 years ago

Where might you see a light wave with a large amplitude? Why?

2 answers:

7 0

A light wave is important because it tells about the intensity or brightness of a light relative to another light wave of the same wave length. It is a measure of how much energy the wave carries.

Diano4ka-milaya [45]3 years ago

6 0

One place you may find a high amplitude light wave is light that comes from studio lights, because a light wave amplitude tells about the intensity or brightness of a light relative to another light wave of the same wavelength.

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aivan3 [116]

The reason for people to swim easier in salt water than fresh water is because of buoyancy

Explanation:

In fresh water there is lack of minerals and has fresh water alone. The density of fresh water is 1000 kg/m³. Hence, in fresh water cannot exert the suitable buoyancy for the swimmer to float easier than that of salt water.

But in Salt water due to enrichment of salts and minerals it is found that salt water has more density than fresh water. Here the salt water offers more buoyancy to the swimmer to lift him up in the water surface and to swim faster and easier than fresh water.

It is similar to that egg floats in the salt water and sinks inside the fresh water because of its own body weight.

4 0

2 years ago

Read 2 more answers

A 3250 N car is pushed a distance of 35 m the power was 11375 J, how long did it take?

irakobra [83]

Answer:

10.8s

Explanation:

Given parameters:

Force on the car = 3250N

Distance = 35m

Power = 11375W

Unknown:

Time taken = ?

Solution:

To solve this problem;

Power is the rate at which work is done

Power = $\frac{work done }{time}$

Work done = force x distance = 3250 x 35 = 123200J

Now;

11375 = $\frac{123200}{t}$

11375t = 123200

t = 10.8s

5 0

3 years ago

If a dog walks north for 10 meters and then east for 10 meters, what is the direction of its displacement?

Katyanochek1 [597]

The direction of its displacement wil be

c.northeast

In fact, the dog walks north for 10 meters and east for another 10 meters. The path of the dog can be represented with two vectors, A pointing north (of magnitude 10 meters) and B pointing east (of magnitude 10 meters). The direction of the resultant vector (due to east) will be given by

$tan \theta =\frac{A}{B}=\frac{10}{10}=1$

$\theta=tan^{-1} (1)=45^{\circ}$

and the direction will be north-east.

5 0

3 years ago

A projectile is launched diagonally into the air and has a hang time of 24.5 seconds. Approximately how much time is required fo

Rasek [7]

Answer:

$t=12.25\ seconds$

Explanation:

<u>Diagonal Launch </u>

It's referred to as a situation where an object is thrown in free air forming an angle with the horizontal. The object then describes a known path called a parabola, where there are x and y components of the speed, displacement, and acceleration.

The object will eventually reach its maximum height (apex) and then it will return to the height from which it was launched. The equation for the height at any time t is

$x=v_ocos\theta t$

$\displaystyle y=y_o+v_osin\theta \ t-\frac{gt^2}{2}$

Where vo is the magnitude of the initial velocity, $\theta$ is the angle, t is the time and g is the acceleration of gravity

The maximum height the object can reach can be computed as

$\displaystyle t=\frac{v_osin\theta}{g}$

There are two times where the value of y is $y_o$ when t=0 (at launching time) and when it goes back to the same level. We need to find that time t by making $y=y_o$