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Crazy boy [7]
3 years ago
5

Where might you see a light wave with a large amplitude? Why?

Physics
2 answers:
liraira [26]3 years ago
7 0

A light wave is important because it tells about the intensity or brightness of a light relative to another light wave of the same wave length. It is a measure of how much energy the wave carries.

Diano4ka-milaya [45]3 years ago
6 0

One place you may find a high amplitude light wave is light that comes from studio lights, because a light wave amplitude tells about the intensity or brightness of a light relative to another light wave of the same wavelength.

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A sports car is advertised to be able to stop in a distance of 50.0 m from a speed of 80 km. What is its acceleration and how ma
Flauer [41]

Explanation:

Given that,

Initial speed of the sports car, u = 80 km/h = 22.22 m/s

Final speed of the runner, v = 0

Distance covered by the sports car, d = 80 km = 80000 m

Let a is the acceleration of the sports car.  It can be calculated using third equation of motion as :

v^2-u^2=2ad

a=\dfrac{v^2-u^2}{2d}

a=\dfrac{0-(22.22)^2}{2\times 80000}

a=-0.00308\ m/s^2

Value of g, g=9.8\ m/s^2

a=\dfrac{-0.00308}{9.8}\ m/s^2

a=(-0.000314)\ g\ m/s^2

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3 years ago
The diagram shows two different types of fossils from the
ale4655 [162]

Answer:

I think the answer is A. X: Mold Y: Cast

Explanation:

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3 years ago
A mass weighing pounds is attached to a spring whose constant is lb/ft. The medium offers a damping force that is numerically eq
andreyandreev [35.5K]

Answer:

hello your question has some missing values attached below is the complete question with the missing values

answer :

a) 0.083 secs

b) 0.33 secs

c)  3e^-4/3

Explanation:

Given that

g = 32 ft/s^2 ,  spring constant ( k ) = 2 Ib/ft

initial displacement = 1 ft above equilibrium

mass = weight / g = 4/32 = 1/8

damping force = instanteous velocity  hence  β = 1

a<u>)Calculate the time at which the mass passes through the equilibrium position.</u>

time mass passes through equilibrium = 1/12 seconds = 0.083

<u>b) Calculate the time at which the mass attains its extreme displacement </u>

time when mass attains extreme displacement = 1/3 seconds = 0.33 secs

<u>c) What is the position of the mass at this instant</u>

position = 3e^-4/3

attached below is the detailed solution to the given problem

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2 years ago
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erik [133]

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Explanation:

5 0
3 years ago
In an economy, the demand for labor is given by the equation W = 15 - (1/200) L and the supply of labor is given by the equation
mr_godi [17]

Answer:

the equilibrium wage rate is 10  and the equilibrium quantity of labor is 1000 workers

Explanation:

The equilibrium wage rate and the equilibrium quantity of labor are found as the point where the equation of demand intercepts the equation of supply, so the equilibrium quantity of labor is:

W_{Demand} = W_{Supply}

15 - (1/200) L = 5 + (1/200) L

15 - 5 =  (1/200) L +  (1/200) L

10 = (2/200) L

(10*200)/2 = L

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Then, the equilibrium wage rate is calculated using either the equation of demand for labor or the equation of supply of labor. If we use the equation of demand for labor, we get:

W = 15 - (1/200) L

W = 15 - (1/200) 1000

W = 10

Finally, the equilibrium wage rate is 10 and the equilibrium quantity of labor is 1000 workers

7 0
3 years ago
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