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lisov135 [29]
3 years ago
5

a car with a mass of 100 kg is stopped on the side of the road after getting a flat tire. the two people that were riding in the

car get out and begin to push the car from rest to a nearby gas station. The car travels 50 meters in 40 seconds. Determine the speed of the car in these 40 seconds.
Physics
1 answer:
notsponge [240]3 years ago
3 0

Answer:

Please mark me brainliest and thank me and rate me

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When a certain string is clamped at both ends, the lowest four resonant frequencies are 50, 100, 150, and 200 Hz. When the strin
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Answer:

Explanation:

Given

Lowest four resonance frequencies are given with magnitude

50,100,150 and 200 Hz

The frequency of vibrating string is given by

f=\frac{n}{2L}\sqrt{\frac{T}{\mu }}

where n=1,2,3 or ...n

L=Length of string

T=Tension

\mu =Mass per unit length

When string is clamped at mid-point

Effecting length becomes L'=0.5 L

Thus new Frequency becomes

f' =\frac{n}{L}\sqrt{\frac{T}{\mu }}

i.e. New frequency is double of old

so new lowest four resonant frequencies are 100,200,300 and 400 Hz      

4 0
3 years ago
The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energ
olya-2409 [2.1K]

Answer: 8400 J

Explanation:

The formula referenced in the question is:

Q=m. c. \Delta T  

Where:

Q  is the thermal energy

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\Delta T=20\°C  is the variation in temperature

Solving:

Q=(0.1 kg)(4200 \frac{J}{kg\°C})(20\°C)  

Q=8400 J  This is the thermal energy released

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