Question

A 36.5-g glass thermometer reads 23.6 ∘C before it is placed in 145 mL of water. When the water and thermometer come to equilibrium, the thermometer reads 40.8 ∘C. Ignore the mass of fluid inside the glass thermometer. The value of specific heat for water is 4186 J/kg⋅C∘, and for glass is 840 J/kg⋅C∘.

Answer 1

The initial temperature of the water was $41.6688^{0} C$.

Given,

Weight of glass 36.5g

specific heat for glass is 840 J/kg⋅C∘.

Initial temperature of glass was  $23.6^{0} C$.

Weight of water is 145*1=145g (Density*Volume=145ml*1g/ml)

Temperature final was $40.8^{0} C$.

specific heat for water is 4186 J/kgâ‹…Câˆ

(m of glass)(Cp of glass)(Tf_glass-Ti_glass) = (m of water)(Cp of water)(Ti_water - Tf_water)

36.5*840*(40.8-23.6)=145*4186*(Ti_water - 40.8)

Ti_water=$41.6688^{0} C$

Specific heat

In thermodynamics, a material's specific heat capacity, or massic heat capacity as it is sometimes known, is equal to the heat capacity of a sample of the substance divided by the mass of the sample (symbol cp). Informally, it is the quantity of heat needed to raise a substance's temperature by one degree for every unit of mass that is added to it. joule per kelvin per kilogram, or Jkg1K1, is the SI unit for specific heat capacity. For instance, the amount of energy needed to increase the temperature of 1 kilogram of water by 1 K is 4184 joules, making water's specific heat capacity 4184 J kg 1 K 1.

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