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Dafna1 [17]
3 years ago
15

Based on the free-body diagram, the net force acting on this wheelbarrow is {blank} N.

Physics
2 answers:
Semenov [28]3 years ago
5 0

Answer:

diagram?

Explanation:

viva [34]3 years ago
4 0

Answer:

Explanation:

WHERE IS THE FIGURE?

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Assuming a nearly frictionless ride, what can you say about a roller coaster’s potential and kinetic energy from the top to the
ArbitrLikvidat [17]
The mechanical energy of the roller coaster is sum of kinetic energy K and gravitational potential energy U:
E=K+U
where
K= \frac{1}{2}mv^2 is the kinetic energy
U=mgh is the gravitational potential energy

Since the ride is frictionless, the total mechanical energy E is conserved during the ride. Therefore, at the top of the hill, the potential energy is maximum, because h (the height) is maximum, and this means the kinetic energy is minimum (because the sum of K and U is constant), so the velocity will be minimum. Viceversa, at the bottom of the hill, the potential energy will be minimum (because h is minimum), so the kinetic energy K will be maximum, and the velocity v of the roller coaster will be maximum.
4 0
3 years ago
Two point masses are held in place a distance d apart. Another point mass M is midway between them. M is then displaced a small
sasho [114]
THAT LINK IS A VIRUS NEVER GO TO A LINK and if you go to “goggle” you should see a camera icon and take a picture of the question and get the answer there
5 0
3 years ago
Which property of matter is conserved in chemical reactions and shown by balanced equations?
bezimeni [28]

Answer:

Mass.

Explanation:

I took the quiz and got the answer right

8 0
2 years ago
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During free fall, what happens to the gravitational potential energy of a ball?​
ArbitrLikvidat [17]
The GPE is converted into kinetic energy as it falls.
4 0
3 years ago
A car is moving at a constant speed of 14 m/s when the driver presses down on the gas pedal and accelerates for 14 s with an acc
Vinil7 [7]

acceleration of car is 1.8 m/s^2

time = 14 s

initial speed = 14 m/s

so the final speed is calculated by

v_f = v_i + at

v_f = 14 + 14 * 1.8

v_f = 39.2 m/s

so the total distance moved in this interval of time is

d = \frac{v_f + v_i}{2}* t

d = \frac{39.2 + 14}{2}* 14

d = 372.4 m

now the average speed is given as

v = \frac{d}{t}

v = \frac{372.4}{14}

v = 26.6 m/s

so the average speed will be 26.6 m/s

7 0
3 years ago
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