Question

How many molecules in 5.68 g of ozone (O3)

Answer 1

Answer:

$\boxed{\sf no.\ of \ molecules = 7.13 \times 10^{22} \ molecules}$

Explanation:

Given data::

Mass in g = m = 5.68 g

Molar mass = M = (16)3 = 48 g/mol

Avogadro's number = $N_A$ = 6.023 × 10²³

Required:

No. of molecules = ?

Formula:

$\displaystyle no.\ of \ molecules = \frac{m}{M} \times N_A$

Solution:

Put the givens in the above formula

$\displaystyle no. \ of \ molecules =\frac{5.68}{48} \times 6.023 \times 10^{23}\\\\no. \ of\ molecules = 0.12 \times 6.023 \times 10^{23}\\\\no. \ of \ molecules = 0.713\times 10^{23}\\\\no.\ of \ molecules = 7.13 \times 10^{22} \ molecules\\\\\rule[225]{225}{2}$