How can a right triangular cross-section be created from a right triangle ?

Mathematics

1 answer:

svetlana [45]2 years ago

5 0

Answer:

in a triangle prism each cross section parallel to the triangular base is a triangle congruent to the base

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Plot two points that are 3units from Point C and also share the same y-coordinate as Point C.

egoroff_w [7]

The two points at a distance of 3 units from C with the same y coordinate are (-3, -5) and (-9, -5).

Step-by-step explanation:

Step 1:

First, we must plot the point C on the graph. Point C is on the third quadrant so the x value and the y value are negative.

The coordinate of C is (-6, -5).

We need to plot two points that are 3 units away from point C but have the same y coordinate i.e. y = -5.

Step 2:

So assume the two other points are A and B.

The y coordinates of A and B are -5. Only the x coordinate varies. So in order to get the coordinates of point A and B, we add and subtract 3 from the x coordinate of point C.

Point A = (-6+3, -5) = (-3,-5).

Point B = (-6-3, -5) = (-9, -5).

So two points at a distance of 3 units from C with the same y coordinate are (-3, -5) and (-9, -5).

6 0

3 years ago

Suppose that many large samples were taken from population A, which is normally distributed, and population c, which is not norm

OLEGan [10]

Answer:

Population A

Step-by-step explanation:

Think about. If population A already known for normally distribution AND you take large samples. The rest would still be distributed, Which keeps population A a Normal Distribution.

but Population C is nor normally distributed, so if you take away large samples. it will deteriorate its distribution so it won't get any better or in this case, normal. so. it is Population A.

4 0

4 years ago

Read 2 more answers

In an automobile parts factory, for every 175 carburetors 3 are found to be defective. At that rate how many carbureatots out of

Furkat [3]

Answer:

At the same rate 18 carburetors out of 1,050 could be expected to be detective.

Step-by-step explanation:

The number of carburetors tested = 175

Defective pieces out o f 175 = 3

So, ratio of defected to tested = 3 : 175

Now, the number of carburetors tested in second batch = 1,050