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3 years ago

The formula for chlorine acid is

1 answer:

5 0

The correct terminology for chlorine acid is Hydrochloric Acid. The formula for that is HCl. This is because H has an ionic charge of +1 and Cl has an ionic charge of -1. Thus, they will combine to form HCl. Also, H is in front because almost all acids will have H in front.

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If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc

hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

$Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $Al_2O_3$ = $\frac{16.9\times 1000g}{102g/mol}=165.7moles$

moles of $NaOH$ = $\frac{57.4\times 1000g}{40g/mol}=1435moles$

moles of $HF$ = $\frac{57.4\times 1000g}{20g/mol}=2870moles$

As 1 mole of $Al_2O_3$ reacts with 6 moles of $NaOH$

166 moles of $Al_2O_3$ reacts with = $\frac{6}{1}\times 166=996$ moles of $NaOH$

As 1 mole of $Al_2O_3$ reacts with 12 moles of $HF$

166 moles of $Al_2O_3$ reacts with = $\frac{12}{1}\times 166=1992$ moles of $HF$

Thus $Al_2O_3$ is the limiting reagent.

As 1 mole of $Al_2O_3$ produces = 2 moles of cryolite

166 moles of $Al_2O_3$ reacts with = $\frac{2}{1}\times 166=332$ moles of cryolite

Mass of cryolite $(Na_3AlF_6)$ = $moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg$

Thus 69.72 kg of cryolite will be produced.

8 0

3 years ago

Last question, I promise!!!!!! ... :>

VikaD [51]

Answer:

Which question?

Explanation:

3 0

3 years ago

Read 2 more answers

When the highest occupied energy level of an atom is completely full of electrons, the atom is _____________________________?

scoundrel [369]

The answer is a valence electron

4 0

3 years ago

Which total mass of iron is necessary to produce 1.00 mole of copper?

Harman [31]

1 mole Fe produces 1 mole Cu
<span> molar mass of Fe is 55.8 g / mole

answer: </span><span>55.8g</span>

4 0

3 years ago

You discover a bottle of aqueous sodium chloride of unknown molarity. However, the bottle says that there are 0.75 moles of NaCl

lara31 [8.8K]

To calculate the molarity you only need to know the number of moles in the solution and the volume of that solution. This exercise gives both and with that you divide moles by volume(usually in liters).

500 ml equals 0,5 L
molarity= number of moles/ volume
molarity=0,75 x 0,5
= 0,375 mol/L

6 0

3 years ago