Answer:
60.57g of TRIS did you use
Explanation:
The concentration of the Tris solution buffer is 0.5 molar (That is, 0.5 moles per liter). As you need to make 1L, you need to have in the solution <em>0.5 moles of TRIS.</em>
<em />
To convert these moles of TRIS to grams you need to use the molecular weight of TRIS base (121.14g/mol), thus:
0.5 moles TRIS * (121.14g / mol) =
<h3>60.57g of TRIS did you use</h3>
I think the correct answer from the choices listed above is the second option. When two hydrogen atoms enter the ETS as part of either NADH or FADH2, the two hydrogen atoms are split into two H+ and two electrons. Hope this answers the questions.
This may seem confusing because they give you two masses, but all you have to do is pick one to do the calculations. Personally, I would pick O2, since the molar mass is easier to calculate. The answer would be 3.3 g (rounded for sig figs). To get this, first take the 5.9 grams of O2 and convert it to moles by dividing by the molar mass of oxygen gas, which is 32. Then, multiply both by the mole-mole ratio, which is 2:2, or simply 1:1. After that, multiply that by 18g, which is the molar mass of water to get grams of water.
REMEMBER, you have to write and balance the chemical equation before you can do any of that work.
That happens to be CH4 + 2O2 => CO2 + 2H2O
Explanation:
an increase in concentration increases the rate of the reaction. This is because there are more reactant particles available which allows for more effective collisions between reactant particles in a given period of time. More effective collisions bring about a faster rate of reaction.
