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1 year ago

Explain the relation between Joule and Erg.

Physics

2 answers:

LekaFEV [45]1 year ago

8 0

Answer:

Both erg and Joule are units of Energy in the CGS and S.I system respectively.

Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.

Explanation:

1 Joule = 107 erg ⇒ 107 kg m2/s2.

Varvara68 [4.7K]1 year ago

6 0

==> One erg of energy is the amount of work done when one dyne of force acts through a distance of one centimeter.

==> One Joule of energy is the amount of work done when one Newton of force (100,000 dynes) acts through a distance of one meter (100 centimeters).

==> That makes one Joule the same amount of energy as 10 million (10⁷) dynes.

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2 years ago

A 3.50 kg block is pushed along a horizontal floor by a force of magnitude 15.0 N at an angle θ = 30.0° with the horizontal. The

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Answer :

The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².

Explanation :

Given that,

Mass of block = 3.50

Angle = 30°

Force = 15.0 N

Coefficient of kinetic friction = 0.250

We need to calculate the frictional force

Using formula of frictional force

$F_{k}=\mu N$

$F_{k}=\mu (F\sin\theta+mg)$

$F_{k}=0.250\times(15\times\sin30^{\circ}+3.50\times9.8)$

$F_{k}=0.250\times41.8$

$F_{k}=10.45\ N$

(II). We need to calculate the block's acceleration

Using newton's second law of motion

$F=ma$

$a=\dfrac{F}{m}$

$a=\dfrac{F\cos\theta-F_{k}}{m}$

$a=\dfrac{15.0\cos30^{\circ}-10.45}{3.50}$

$a=0.73\ m/s^2$

Hence, The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².

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3 years ago

Explain, step by step, how to calculate the amount of current (I) that will go through the resistor in this circuit

anygoal [31]

Answer:

0.03 A

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Resistor (R) = 470 Ω

Current (I) =?

From ohm's law, the voltage, current and resistor are related by the following formula:

Voltage = current × resistor

V = IR

With the above formula, we can obtain the current in the circuit as follow:

Voltage (V) = 12 V

Resistor (R) = 470 Ω

Current (I) =?

V = IR

12 = I × 470

Divide both side by 470

I = 12 / 470

I = 0.03 A

Thus, the current in the circuit is 0.03 A

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2 years ago

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Friction provides the force needed for a car to travel around a flat, circular race track. What is the maximum speed at which a

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Answer:

Maximum speed of the car is 17.37 m/s.

Explanation:

Given that,

Radius of the circular track, r = 79 m

The coefficient of friction, $\mu=0.39$

To find,

The maximum speed of car.

Solution,

Let v is the maximum speed of the car at which it can safely travel. It can be calculated by balancing the centripetal force and the gravitational force acting on it as :

$v=\sqrt{\mu rg}$

$v=\sqrt{0.39\times 79\times 9.8}$

v = 17.37 m/s

So, the maximum speed of the car is 17.37 m/s.

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3 years ago

Which nutrient is the most difficult to break down and, thus, is generally used last for energy in the body?

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Answer:

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Explanation:

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3 years ago

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Explain the relation between Joule and Erg.​

Explain the relation between Joule and Erg.