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2 years ago

Explain the relation between Joule and Erg.

Physics

2 answers:

LekaFEV [45]2 years ago

8 0

Answer:

Both erg and Joule are units of Energy in the CGS and S.I system respectively.

Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.

Explanation:

1 Joule = 107 erg ⇒ 107 kg m2/s2.

Varvara68 [4.7K]2 years ago

6 0

==> One erg of energy is the amount of work done when one dyne of force acts through a distance of one centimeter.

==> One Joule of energy is the amount of work done when one Newton of force (100,000 dynes) acts through a distance of one meter (100 centimeters).

==> That makes one Joule the same amount of energy as 10 million (10⁷) dynes.

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The charges of two particles are as follows: Q1=2 x 10 -8 C and Q2 = 3 x 10 -7 C. Find the magnitude of the force between these

Fantom [35]

Answer:

F = 3.86 x 10⁻⁶ N

Explanation:

First, we will find the distance between the two particles:

$r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2}\\$

where,

r = distance between the particles = ?

(x₁, y₁, z₁) = (2, 5, 1)

(x₂, y₂, z₂) = (3, 2, 3)

Therefore,

$r = \sqrt{(3-2)^2+(2-5)^2+(3-1)^2}\\r = 3.741\ m\\$

Now, we will calculate the magnitude of the force between the charges by using Coulomb's Law:

$F = \frac{kq_{1}q_{2}}{r^2}\\$

where,

F = magnitude of force = ?

k = Coulomb's Constant = 9 x 10⁹ Nm²/C²

q₁ = magnitude of first charge = 2 x 10⁻⁸ C

q₂ = magnitude of second charge = 3 x 10⁻⁷ C

r = distance between the charges = 3.741 m

Therefore,

$F = \frac{(9\ x\ 10^9\ Nm^2/C^2)(2\ x\ 10^{-8}\ C)(3\ x\ 10^{-7}\ C)}{(3.741\ m)^2}\\$

F = 3.86 x 10⁻⁶ N

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3 years ago

A real gas will behave most like an ideal gas under conditions of ________.

KengaRu [80]

Answer: high temperature and low pressure

Explanation:

The Ideal Gas equation is:

$P.V=n.R.T$

Where:

$P$ is the pressure of the gas

$V$ is the volume of the gas

$n$ the number of moles of gas

$R=0.0821\frac{L.atm}{mol.K}$ is the gas constant

$T$ is the absolute temperature of the gas in Kelvin

According to this law, molecules in gaseous state do not exert any force among them (attraction or repulsion) and the volume of these molecules is small, therefore negligible in comparison with the volume of the container that contains them.

Now, real gases can behave approximately to an ideal gas, under the conditions described above and taking into account the following:

When temperature is high a real gas approximates to ideal gas, because the molecules move quickly, preventing the repulsion or attraction forces to take effect. In addition, at low pressures, the volume of molecules is negligible.

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3 years ago

A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the

Anni [7]

Answer:

$I=38.181\ A$ is the current through the body of the man.

$E=34.5\ J$ energy dissipated.

Explanation:

Given:

time for which the current lasted, $t=43\times 10^{-6}\ s$

potential difference between the feet, $V=21000\ V$

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Now, from the Ohm's law we have:

$I=\frac{V}{R}$

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3 years ago

What is the tangent function used to find and what are its units

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The functions of angles are used to find unknown lengths or angles that can't be measured, in terms of known quantities. The trig functions of angles are ratios of lengths, so they're bare naked numbers without units.

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3 years ago

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kvv77 [185]

Hi there!

We can use the rotational equivalent of Newton's Second Law:

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α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

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3 years ago

Explain the relation between Joule and Erg.​

Explain the relation between Joule and Erg.