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Oxana [17]
2 years ago
10

Explain the relation between Joule and Erg.​

Physics
2 answers:
LekaFEV [45]2 years ago
8 0

Answer:

Both erg and Joule are units of Energy in the CGS and S.I system respectively.

Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.

Explanation:

1 Joule = 107 erg ⇒ 107 kg m2/s2.

Varvara68 [4.7K]2 years ago
6 0

==>  One erg of energy is the amount of work done when one dyne of force acts through a distance of one centimeter.

==>  One Joule of energy is the amount of work done when one Newton of force (100,000 dynes) acts through a distance of one meter (100 centimeters).

==>  That makes one Joule the same amount of energy as 10 million (10⁷) dynes.

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the force of friction between a 1000 kg car and the road is 10000 N, what is the fastest acceleration the car can achieve?​
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A humanoid skeleton is found buried in the ashes of a volcano that erupted between 10,000 and 12,000 years ago. when scientists
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where t is the number of half-lives, in this case 2. Thus, only about 1/4 of the original amount will be left. 
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Why is it safe to watch an eclipse of the Moon but not an eclipse of the Sun
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8 0
4 years ago
Water flows through a horizontal nozzle in steady flow at the rate of 10m3/s. The inlet and outlet diameters are d1 = 0.5m and d2
Dvinal [7]

Answer:

P₁ = 2.215 10⁷ Pa, F₁ = 4.3 106 N,

Explanation:

This problem of fluid mechanics let's start with the continuity equation to find the speed of water output

        Q = A v

        v = Q / A

The area of ​​a circle is

       A = π r² = π d² / 4

Let's look at the speeds at each point

       v₁ = Q / A₁ = Q 4 /π d₁²

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       v₁ = 50.93 m / s

       v₂ = Q / A₂

       v₂ = 10 4 /π 0.25²

       v₂ = 203.72 m / s

Now we can use Bernoulli's equation in the colon

       P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

Since the tube is horizontal y₁ = y₂. The output pressure is P₂ = Patm = 1.013 10⁵ Pa, let's clear

       P₁ = P2 + ½ rho (v₂² - v₁²)

      P₁ = 1.013 10⁵ + ½ 1000 (203.72² - 50.93²)

      P₁ = 1.013 10⁵ + 2.205 10⁷

      P₁ = 2.215 10⁷ Pa

la definicion de presion es

      P₁ = F₁/A₁

     F₁ = P₁ A₁

     F₁ = 2.215 10⁷ pi d₁²/4

     F₁ = 2.215 10⁷ pi 0.5²/4

     F₁ = 4.3 106 N

     

6 0
3 years ago
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