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Oxana [17]
1 year ago
10

Explain the relation between Joule and Erg.​

Physics
2 answers:
LekaFEV [45]1 year ago
8 0

Answer:

Both erg and Joule are units of Energy in the CGS and S.I system respectively.

Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.

Explanation:

1 Joule = 107 erg ⇒ 107 kg m2/s2.

Varvara68 [4.7K]1 year ago
6 0

==>  One erg of energy is the amount of work done when one dyne of force acts through a distance of one centimeter.

==>  One Joule of energy is the amount of work done when one Newton of force (100,000 dynes) acts through a distance of one meter (100 centimeters).

==>  That makes one Joule the same amount of energy as 10 million (10⁷) dynes.

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Sound waves need a medium to move through in order to keep moving. Through which of the following would sound travel the slowest
Troyanec [42]

Answer:A air

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8 0
3 years ago
Read 2 more answers
A spring gun is made by compressing a spring in a tube and then latching the spring at
inn [45]

Answer:

a)v=13.2171\,m.s^{-1}

b)H=8.9605\,m

Explanation:

Given:

mass of bullet, m=4.97\times 10^{-3}\,kg

compression of the spring, \Delta x=0.0476\,m

force required for the given compression, F=9.12 \,N

(a)

We know

F=m.a

where:

a= acceleration

9.12=4.97\times 10^{-3}\times a

a\approx 1835\,m.s^{-2}\\

we have:

initial velocity,u=0\,m.s^{-1}

Using the eq. of motion:

v^2=u^2+2a.\Delta x

where:

v= final velocity after the separation of spring with the bullet.

v^2= 0^2+2\times 1835\times 0.0476

v=13.2171\,m.s^{-1}

(b)

Now, in vertical direction we take the above velocity as the initial velocity "u"

so,

u=13.2171\,m.s^{-1}

∵At maximum height the final velocity will be zero

v=0\,m.s^{-1}

Using the equation of motion:

v^2=u^2-2g.h

where:

h= height

g= acceleration due to gravity

0^2=13.2171^2-2\times 9.8\times h

h=8.9129\,m

is the height from the release position of the spring.

So, the height from the latched position be:

H=h+\Delta x

H=8.9129+0.0476

H=8.9605\,m

4 0
3 years ago
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Lana71 [14]

Answer:

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Arte-miy333 [17]

Length of the slope is given as

L = 15 m

also the inclination is given as

\theta = 30 degree

now the horizontal displacement is let say "x"

now from geometry we can say

\frac{x}{L} = cos30

x = L cos30

now substitute all values in it

x = 15 * cos30

x = 12.99 m

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What is it called when the moon passes through the penumbra of Earth’s shadow?(1 point)
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