All categories

2 years ago

An ant can travel approximately 30 meters per minute. How many meters could an ant move in 45 minutes.

Physics

1 answer:

Nastasia [14]2 years ago

8 0

Answer:

From what I see, it's saying that every minute, the ant can move 30 meters. So how many meter would it move in 45 minutes?

30 meters = 1 min

x meters = 45 min

1 min x 45 = 45 min

30 meters x 45 = 1,350 meters

So, I believe the answer would be 1,350 meters.

hope this helps. :>

You might be interested in

A force of 1.5 × 102 N is exerted on a charge of 1.4 × 10–7 C that is traveling at an angle of 75° to a magnetic field.

Marysya12 [62]

Option (B) is correct.The magnetic field strength=8.5 x 10² T

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

B=8.5 x 10² T

6 0

3 years ago

Read 2 more answers

A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11-

Aleks04 [339]

Answer:

$a=2.4\ m/s^2$

Explanation:

Given that,

Initial speed of a car, u = 13 m/s

Final speed of a car, v = 25 m/s

Time, t = 5 s

We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2$

So, the acceleration of the car is $2.4\ m/s^2$ .

7 0

3 years ago

In a microwave oven, electrons describe circular motion in a magnetic field within a special tube called amagnetron; as you'll l

QveST [7]

Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

Explanation:

Given that,

Diameter = 2.62 mm

Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

$B=\dfrac{2\pi mf}{e}$

Where, f = frequency

e = charge of electron

Put the value into the formula

$B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}$

$B=0.077\ T$

(B). We need to calculate the energy of electron

Using formula of energy

$E=\dfrac{1}{2}m(r\omega)^2$

$E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2$

$E=1.4249\times10^{-16}\ J$

The energy in eV

$1 eV=1.6\times10^{-16}\ J$

$E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}$

$E=0.8906\ eV$

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

5 0

3 years ago

THE ELECTROMAGNET SPECTRUM ONLY HAS WHICH SHAPE OF WAVE?

brilliants [131]

Answer: Transverse

Explanation: Transverse waves possess a vertical wave motion and a horizontal particle motion.

4 0

2 years ago

A paleontologist estimates that when a particular rock formed, it contained 12 mg of the radioactive isotope potassium-40, which

leva [86]

Answer:

$t = 2.52 billion \:years$

Explanation:

As we know by radioactivity law

$N = N_o e^{-\lambda t}$

so here we will have

$N = 3 mg$

$N_o = 12 mg$

now we will have

$3 = 12 e^{-\lambda t}$

$\lambda t = ln 4$

now we also know that

$\lambda = \frac{ln2}{1.26 \times 10^6 yrs}$

$t = 1.26\times 10^6\times \frac{ln4}{ln2}$

$t = 2.52 billion \:years$

7 0

2 years ago