A ball at rest hit by a golf club has initial velocity zero. The ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
<h3>What is force?</h3>
The action of push or pull which changes the state of motion or rest of a body is called force.
The club applies a force of 700N to the ball and the time of impact is 0.05s. The mass of ball is 0.10kg.
The impact force F is equal to the change in momentum of the ball multiplied by time of impact t. The momentum is the product of mass m and velocity v after impact.
F= (mv -mu) x t
The ball is initially at rest, so u =0
F = mvt
Substitute the values into the above equation of force to find the velocity.
v = F / mt
v =700 / (0.10 x 0.05)
v = 1.4 x 10⁵ m/s
Thus, the ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
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If the experiment had been repeated with frequencies 10 times lower than those in table 5.2, then Vc will increase 10 times to the values given in the table.
<h3 /><h3>What is frequency?</h3>
It is the number of oscillations per second of the sinusoidal wave.
Vc is the voltage across the capacitor and Xc is the capacitive reactance.
Xc = - 1/2πfC
where f is the frequency and C is the capacitance of the capacitor.
If the frequency is lowered, the potential difference will increase because frequency is inversely proportional to the voltage.
Thus, Vc will increase by lowering the frequency by 10 times.
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<span>c. increases across a period and decreases down a group.</span>
To find the answer, take 55 and divide it by 1.85 to get the thickness of one card. In this case the answer would be 29.72973 cm. each.