All categories

3 years ago

A bag is dropped onto the street from the roof of a 32 m high building. How long does it take for the bag to fall?

Physics

1 answer:

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

Explanation:

h = ½at²

t = √(2h/a)

t = √(2(32)/9.8)

t = 2.5555062... 2.6 s

You might be interested in

Which creates energy used by the other system to help you exercise?

jasenka [17]

Answer:

There are many different systems involved in when we exercise, the three main ones are the Respiratory system which is involved in breathing the circulatory system which is about circulation of blood around the body and finally the muscular system and finally the Muscular system which is about how we move.

Explanation:

MRK ME BRAINLIEST PLZZZZZZZZ

8 0

3 years ago

Read 2 more answers

Someone please help me

Basile [38]

Photosynthesis is the name given to the set of chemical reactions performed by plants to convert energy from the sun into chemical energy in the form of sugar. Specifically, plants use energy from sunlight to react carbon dioxide and water to produce sugar (glucose) and oxygen. Many reactions occur, but the overall chemical reaction for photosynthesis is:

6 CO2 + 6 H2O + light → C6H12O6 + 6 O2
So it would be C, I hope this helped! :)

8 0

3 years ago

What is the pressure drop due to the bernoulli effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire

Paul [167]

Answer:

$\Delta P=1581357.92\ Pa$

Explanation:

Given:

diameter of hose pipe, $D=0.09\ m$

diameter of nozzle, $d=0.03\ m$

volume flow rate, $\dot{V}=40\ L.s^{-1}=0.04\ m^3.s^{-1}$

Now, flow velocity in hose:

$v_h=\frac{\dot V}{\pi.D^2\div 4}$

$v_h=\frac{0.04\times 4}{\pi\times 0.09^2}$

$v_h=6.2876\ m.s^{-1}$

Now, flow velocity in nozzle:

$v_n=\frac{\dot V}{\pi.d^2\div 4}$

$v_n=\frac{0.04\times 4}{\pi\times 0.03^2}$

$v_n=56.5884\ m.s^{-1}$

We know the Bernoulli's equation:

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}+Z_1=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}+Z_2$

when the two points are at same height then the eq. becomes

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}$

$\Delta P=\frac{\rho(v_n^2-v_h^2)}{2}$

$\Delta P=\frac{1000(56.5884^2-6.2876^2)}{2}$

$\Delta P=1581357.92\ Pa$

8 0

3 years ago

Which term describes the amount of heat needed to change 1 kg of a substance from solid to liquid at its melting point? A. Speci

Lorico [155]

It is called the specific latent heat of fusion. C.

This is the heat change required in changing 1kg of a solid to its liquid and it occurs at the melting point. It is not associated with temperature change.

If it is to convert 1kg of liquid to vapor at its boiling point it is called the latent heat of vaporization.

6 0

3 years ago

As an example, a 4.00-kg aluminum ball has an apparent mass of 2.10 kg when submerged in a particular liquid: calculate the dens

azamat

Answer:

1.2825 * 10^3 kg/m³

Explanation:

Given that :

Mass of aluminum ball (m1) = 4kg

Apparent mass of ball (m2) = 2.10 kg

Density of aluminum (d1) = 2.7 * 10^3 kg/m³

Density of liquid (d2) =?

Using the relation :

d1 / d2 = m1 / (m2 - m1)

(2.7 * 10^3) / d2 = 4 / (4 - 2.10)

2700 / d2 = 4 / 1.9

4 * d2 = 2700 * 1.9

4 * d2 = 5130

d2 = 5130 / 4

d2 = 1282.5 kg/m³

Hence, density of liquid = 1.2825 * 10^3

6 0

3 years ago