Answer:
a)
b)
Explanation:
Given:
height of water in one arm of the u-tube,
a)
Gauge pressure at the water-mercury interface,:
we've the density of the water
b)
Now the same pressure is balanced by the mercury column in the other arm of the tube:
<u>Now the difference in the column is :</u>
Answer:
Explanation:
= normal force acting on the coin
Normal force in the upward direction balances the weight of the coin, hence
= frequency of rotation
Angular velocity of turntable is hence given as
= distance from the axis of rotation
= minimum coefficient of static friction
static frictional force is given as
The static frictional force provides the necessary centripetal force , hence
Centripetal force = Static frictional force
The coefficient of static friction between the chair and the floor is 0.67
Explanation:
Given:
Weight of the chair = 25kg
Force = 165 N (F_applied)
Force = 127 N (F_max)
To find: Coefficient of static friction
The “coefficient of static friction” between a chair and the floor is defined as the ration of maximum force to the normal force acting on the chair
μ_s=
The F_n is equal to the weight multiplied by its gravity
∴=mg
Thus the coefficient of static friction changes as
μ_s=
μ_{s} =
= 0.67
Answer
given,
wavelength (λ)= 500 n m
thickness of film= 10⁻⁴ cm
refractive index = μ = 1.375
distance traveled is double which is equal to 2 x 10⁻⁴ cm
a) Number of wave
N = 2.91
N = 3
b) phase difference is equal to
Reflection from the first surface has a 180° (½λ) phase change.
There is no phase change for the 2nd surface reflection and there is no phase difference for the 2nd wave having traveled an exact whole number of waves.
net phase difference =
= 270°