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NemiM [27]
2 years ago
5

A body with a mass of 2,000 kg is lifted to a height of 15 m within a time of 15 s. Which one of the following statements concer

ning the action is true?
a. The gravity force on the body is 294,000 N.
b. The potential energy of the body is 30,000 J.
c. The amount of work is 450,000 J.
d. The power exerted is 19,600 W.
Physics
1 answer:
Aleksandr [31]2 years ago
8 0
<span>So we want to know which statement is true for the body of mass m=2000kg that is lifted to a height of h=15m in t=15 s. Lets calculate each of the following: Gravity force on the body is F=m*g=2000*9.81=19620 N so a is FALSE. Potential energy of the body when it is lifted to the height of 15 m is Ep=m*g*h=2000*9.81*15=294300 J so b is FALSE. Work to lift the body is: W=Fg*h=2000*9.81*15= Ep=294300 J so c is FALSE. Power P=W/t=294300/15=19620 W So d is TRUE. </span>
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Heptane is always composed of 84.0% carbon and 16.0% hydrogen. This illustrates the law of multiple proportions. conservation of
BigorU [14]

Heptane is always composed of 84.0% carbon and 16.0% hydrogen. This illustrates the "law of definite proportions".

Answer: Option C

<u>Explanation:</u>

Proust's law states that every chemical compound used to made up of element constituents with constant proportions in terms of its mass and also independent from its sources and synthesis method. In 1779, Joseph Proust gave other names to the Proust's law as, the law of composition or definite proportions or constant compositions.

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3 years ago
A body moving with an acceleration 2 m/s?then what is the change in velocity in 4sec.​
enot [183]

Answer:

As Per Provided Information

Moving body has 2m/s² acceleration

Time taken by body is 4 second

We are asked to find the 'change in velocity' ( ∆V) by the body.

<u>Formula Used here</u>

\boxed{\bf{\Delta \: V \:  =  acceleration \:  \times time \:}}

<u>Substituting </u><u>the </u><u>given </u><u>value</u>

<u>\sf\longrightarrow\Delta\:V \:  = 2 \times 4 \\  \\  \\ \sf\longrightarrow\Delta\:V \:  =8m {s}^{ - 1}</u>

<u>Therefore</u><u>,</u>

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7 0
1 year ago
In a laboratory, it is often convenient to make measurements in centimeters and grams, but SI units are needed for calculations.
zheka24 [161]

Answer:

(a) 0.92 cm= 0.092 m.

(b) 141.64 g=0.14164 kg.

(c) 15. 8 cm³=0.0000158 m³

(d) 63.6 g/cm³= 63600 kg/m³

Explanation:

The International System of Units, abbreviated S.I., also called the International System of Measurements is a system of measurements in which its units are based on fundamental physical phenomena. The units of the S.I. They are the international reference for the indications of all measuring instruments.

The International System of Units (SI) arose from the need to unify and give coherence to a great variety of unit subsystems.

The International System of Units consists of seven basic units, also called fundamental units, which define the corresponding fundamental physical quantities and which allow any physical quantity to be expressed in terms or as a combination of them. The fundamental physical quantities are complemented by two more physical quantities, called supplementary ones.

By combining the basic units, the other units are obtained, called units derived from the International System, and which allow defining any physical quantity.

(a)  The SI unit of length is the meter. Being 1 cm = 0.01 m, then <u><em>0.92 cm= 0.092 m.</em></u>

(b)  The SI unit of mass is kg. Being 1 g = 0.001 kg, then <u><em>141.64 g=0.14164 kg.</em></u>

(c) Being 1 cm³ = 0.000001 m³, then <u><em>15. 8 cm³=0.0000158 m³</em></u>

(d) Being 1 g/cm³= 1000 kg/m³, then <u><em>63.6 g/cm³= 63600 kg/m³</em></u>

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