Answer:
Explanation:
Using Conservation of momentum (total final momentum of system is)
m1•v1f + m2•v2 f + m3•v3 f=0
and it must be zero to equal the original momentum( since the original body is at rest).
Given that
original mass M=1.82×10^-26
First disintegrate mass m1=5.18×10^-27kg
In y direction V1f=6×10^6 I'm/s
Second disintegrate mass m2=8.5×10^-27kg
In x direction V2f=4×10^6 im/s
Then the third disintegrate will be
m3=M-m1-m2
m3=1.82×10^-26-5.18×10^-27-8.5×10^-27
m3=4.52×10^-27
And the velocity is unknown
Now using the formula above
m1•v1f + m2•v2 f + m3•v3 f=0
m3•V3f= - m1•v1f - m2•v2 f
4.52E-27V3f=-5.18E-27×6E6j - 8.5E-27×4E6 i
Divide thorough by 4.52E-27
V3f= - 6.88×10^6j - 7.52×10^6i
V3f= - 7.52×10^6i - 6.88×10^6j
The final velocity of the third mass disintegrate is 6.88×10^6j - 7.52×10^6i m/s
