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Molodets [167]
2 years ago
13

Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle q1. Is it pus

hing to the right, or to the left?

Physics
1 answer:
ValentinkaMS [17]2 years ago
8 0

The net force on particle particle q1 is 13.06 N towards the left.

<h3>Force on q1 due to q2</h3>

F(12) = kq₁q₂/r₂

F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)

F(12) = -14.41 N  (towards left)

<h3>Force on q1 due to q3</h3>

F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)

F(13) = 1.352 N (towards right)

<h3>Net force on q1</h3>

F(net) = 1.352 N - 14.41 N

F(net) = -13.06 N

Thus, the net force on particle particle q1 is 13.06 N towards the left.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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Which statement did Ernest Rutherford make about atoms?
PtichkaEL [24]

Answer:

Option A

Explanation:

Ernest Rutherford concluded that the atom has a small, dense center which constitutes the mass of the whole atom. He called it a "Nucleus". He also said that most of the space in the atom is empty.

6 0
3 years ago
A gamma ray photon has an energy of 0.91 GeV. (1 GeV = 109 eV.) What is the wavelength of the gamma ray in fm? (1 fm = 10-15 m)?
anastassius [24]

Answer:

\lambda=1.37 fm

Explanation:

The Planck Eistein relation, states that the energy of a photon is proportional to its frequency:

E=h\nu(1)

h is the Plank constant.The frequency of a photon is defined as the speed of light over its wavelength:

\nu=\frac{c}{\lambda}(2)

Replacing (2) in (1):

E=\frac{hc}{\lambda}\\\lambda=\frac{hc}{E}\\\lambda=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{0.91*10^{9}eV}\\\\\lambda=(1.37*10^{-15}m)*\frac{1fm}{10^{-15}m}\\\\\lambda=1.37 fm

6 0
3 years ago
One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat
marin [14]

Answer:

B. 2.77 x 10^{-4} N

Explanation:

The required force can be calculated by:

F = \frac{Kq_{1}q_{2}  }{d^{2} }

Where F is the force between the particles, K is the coulomb's constant (9 x 10^{9} Nm^{2}/C^{2}), q_{1} is the charge on the first particle, q_{2} is the charge on the second particle and d^{2} is the distance between the particles.

So that:

F = \frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9}  }{(0.015)^{2} }

  = \frac{6.2307*10^{-8} }{(2.25*10^{-4} }

  = 2.7692 x 10^{-4}

 The force between the particles is 2.77 x 10^{-4} N.

3 0
3 years ago
What school did Ronald McNair go to and what kind of science did he work in
alina1380 [7]

Answer:

McNair graduated as valedictorian of Carver High School in 1967. In 1971, he received a Bachelor of Science degree in engineering physics, magna cu.m laude, from the North Carolina Agricultural and Technical State University in Greensboro, North Carolina.

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3 years ago
Give an example of how a cell’s structure relates to its function in the body.
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Answer:

The epithelial cell shape and stratification are related to its function. For example, the skin is specialized to act as a "physical" barrier to the outside world. This barrier is both structural (multi-layered) and chemical in nature. Another example is the cells that make up the tubular elements of the kidney.

Explanation:

7 0
3 years ago
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