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kompoz [17]
2 years ago
5

compare and contrast the medical understanding of death (that you have read about and learned about in this chapter) and the pop

ular, typical understanding of death. this is chapter 11 for forensics
Physics
1 answer:
mixer [17]2 years ago
8 0

The medical understanding of death is related to the scientific approach, and the popular understanding is related to the inclusive spiritual and cultural approaches.

<h3 /><h3>What is death for science?</h3>

Death occurs when an individual's cardiorespiratory and brain functions cease due to some factor, thus ending his life.

Popular understanding, on the other hand, is aligned with scientific knowledge, but it is also encompassing cultural and religious teachings, which define topics not proven by science, such as life after death for example.

Therefore, death is a delicate topic for society, and spirituality is the basis found for greater emotional comfort in individuals who suffer significant losses of loved ones.

Find out more about scientific knowledge here:

brainly.com/question/1729104

#SPJ1

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A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (ve
Lemur [1.5K]

The Force on the left hand pole, F' = 0.167N

<h3>What is the force on the left hand pole?</h3>

Force is an agent which produces a change in the motion or state of an object.

Force is a vector quantity.

The general force is calculated as follows:

F = mg/sinθ

m = 17.1 g = 0.0171 kg

g = 9.81 m/s²

θ = 45°

F = 0.0171 * 9.81/sin45

F = 0.237 N

Force on the left hand pole, F' = Fcosθ

F' = 0.237 * cos 45

F' = 0.167N

In conclusion, the force on the left hand pole is the horizontal component of force.

Learn more about force at: brainly.com/question/141439

#SPJ1

5 0
2 years ago
Question 6 (10 points)
horsena [70]

Answer:

a= g = - 9.81 m/s2.

The following equations will be helpful:

a = (vf - vo)/t d = vot + 1/2 at2 vf2 = vo2 + 2ad

When you substitute the specific acceleration due to gravity (g), the equations are as follows:

g = (vf - vo)/t d = vot + 1/2 gt2 vf2 = vo2 + 2gd

If the object is dropped from rest, the initial velocity ("vi") is zero. This further simplifies the equations to these:

g = vf /t d = 1/2 gt2 vf2 = 2gd

The sign convention that we will use for direction is this: "down" is the negative direction. If you are given a velocity such as -5.0 m/s, we will assume that the direction of the velocity vector is down. Also if you are told that an object falls with a velocity of 5.0 m/s, you would substitute -5.0 m/s in your equations. The sign convention would also apply to the acceleration due to gravity as shown above. The direction of the acceleration vector is down (-9.81 m/s2) because the gravitational force causing the acceleration is directed downward.

hope this info helps you out!

7 0
3 years ago
A roller coaster car is going over the top of a 15-m-radius circular rise. The passenger in the roller coaster has a true weight
konstantin123 [22]

Answer:

v = 7.67 m/s

Explanation:

The equation for apparent weight in the situation of weightlessness is given as:

Apparent Weight = m(g - a)

where,

Apparent Weight = 360 N

m = mass passenger = 61.2 kg

a = acceleration of roller coaster

g = acceleration due to gravity = 9.8 m/s²

Therefore,

360 N = (61.2 kg)(9.8 m/s² - a)

9.8 m/s² - a = 360 N/61.2 kg

a = 9.8 m/s² - 5.88 m/s²

a = 3.92 m/s²

Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:

a = v²/r

where,

a = centripetal acceleration = 3.92 m/s²

v = speed of roller coaster = ?

r = radius of circular rise = 15 m

Therefore,

3.92 m/s² = v²/15 m

v² = (3.92 m.s²)(15 m)

v = √(58.8 m²/s²)

<u>v = 7.67 m/s</u>

7 0
3 years ago
An electric hoist is used to lift a 235.0 kg load to a height of 69.0 m in 38.1 s. (a) what is the power of the hoist in kw?
Ugo [173]
Given:\\m=235.0kg\\h=69.0m\\t=38.1s\\g=9.81 \frac{m}{s^2} \\\\Find:\\P=?\\\\Solution:\\\\P= \frac{W}{t}\\\\W=\Delta E_p\\\\E_p_0=0\Rightarrow \Delta E_p=E_p\\\\E_p=mgh \\\\P= \frac{mgh}{t} \\\\P= \frac{235kg\cdot9.81 \frac{m}{s^2}\cdot69m}{38.1s} \approx  4175W=4.175kW
4 0
3 years ago
When the frequency of an electromagnetic wave increases, its energy
OverLord2011 [107]
The energy stays the same
8 0
3 years ago
Read 2 more answers
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