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kompoz [17]
2 years ago
5

compare and contrast the medical understanding of death (that you have read about and learned about in this chapter) and the pop

ular, typical understanding of death. this is chapter 11 for forensics
Physics
1 answer:
mixer [17]2 years ago
8 0

The medical understanding of death is related to the scientific approach, and the popular understanding is related to the inclusive spiritual and cultural approaches.

<h3 /><h3>What is death for science?</h3>

Death occurs when an individual's cardiorespiratory and brain functions cease due to some factor, thus ending his life.

Popular understanding, on the other hand, is aligned with scientific knowledge, but it is also encompassing cultural and religious teachings, which define topics not proven by science, such as life after death for example.

Therefore, death is a delicate topic for society, and spirituality is the basis found for greater emotional comfort in individuals who suffer significant losses of loved ones.

Find out more about scientific knowledge here:

brainly.com/question/1729104

#SPJ1

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The fall of a body on the earth's surface cannot be a complete free fall why ?​
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The power of a lens is defined as the reciprocal of its focal length: P = 1/f. (Thus power is measured in inverse meters, called
Len [333]

Answer:

This the power of combination is given by

P_{combination}=\frac{1}{F}=\frac{d+f_{2}-f_{1}}{f_{2}(d-f_{1})}

Explanation:

Let 'F' be the focal length of the combination of the two lenses and the focal length's of individual lenses be f_{1},f_{2}

We know that focal length is the position of image when object is placed at infinity

Let us place the the object at infinity with respect to the first lens thus the position of image formed by the first lens shall be obtained using lens formula as

\frac{1}{f_{1}}=\frac{1}{u}+\frac{1}{v}

Applying values we get

\frac{1}{f_{1}}=\frac{1}{\infty }+\frac{1}{v}\\\\\Rightarrow \frac{1}{f}=0+\frac{1}{v}\\\\\therefore v=+f_{1}

Now this position of image formed by the first lens act's as object for the second lens, thus we have

\frac{1}{f_{2}}=\frac{1}{-(d-f_{1})}+\frac{1}{v}\\\\\Rightarrow \frac{1}{f_{2}}+\frac{1}{d-f_{1}}=\frac{1}{v}\\\\\therefore \frac{1}{v}=\frac{(d-f_{1})+f_{2}}{f_{2}(d-f_{1})}\\\\=\frac{1}{v}=\frac{d+f_{2}-f_{1}}{f_{2}(d-f_{1})}\\\\\therefore v_{f}=\frac{f_{2}(d-f_{1})}{d+f_{2}-f_{1}}

Since image of an object placed at infinity will be formed at v_{f}=\frac{f_{2}(d-f_{1})}{d+f_{2}-f_{1}} thus the focal length of the combination of the 2 thin lenses will be F=\frac{f_{2}(d-f_{1})}{d+f_{2}-f_{1}}

This the power of combination is given by

P_{combination}=\frac{1}{F}=\frac{d+f_{2}-f_{1}}{f_{2}(d-f_{1})}

(For the sake of question we assume lenses to be convex although the same procedure is valid for all other lenses)

5 0
4 years ago
8.
Leno4ka [110]

Gravitational force is an example of at-a-distance force

Option: C

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Force has both direction and magnitude it is a "vector" quantity. Force is defined as pull or push of an object resulting it to interact with two objects. There are 'Contact forces' and 'At-a-distance forces'. If two interacting objects are not in a physical contact with respect to each other the force is exerted between these two objects called 'at-a-distance' forces. This type of forces consists gravitational forces. Some of the examples of the 'at-a-distance' forces are electrical and magnetic.

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