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kondor19780726 [428]
3 years ago
12

True or false? A tide with the least distance between low and high tides is called a neap tide.

Physics
2 answers:
lord [1]3 years ago
7 0

the only logical answer is true

aksik [14]3 years ago
6 0

The answer is True. Neap tides are when there is the least distance between low and high tides.

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Crystal kick the 3.0 kg soccer ball horizontally off of the top of a building the building is 6.0 m tall and the ball lands 10.0
sattari [20]

Answer:

gametes

nucleic acids

Explanation:

amino acids

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3 0
3 years ago
Which of the following is a limited resource, which can take longer to be replenished than it takes to be used up?
Zarrin [17]
What is the list of choices?
8 0
3 years ago
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Consider four atoms from the second period: lithium, beryllium, boron, carbon, and nitrogen. Which of these emblems has the lowe
xz_007 [3.2K]
If you go to the right along the periodic table, electronegativity increases.
So the larger the column number, the greater the electronegativity.

-Lithium has lowest as it is in the 1st column



-Beryllium (2nd column)
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-Nitrogen (15th column)


6 0
3 years ago
A drop
exis [7]

Answer:

27.5\  m

Explanation:

As we know that volume of cylinder is

v=\pi r^{2} *h

Where v=volume , h= height or thickness and r= radius

Here,

v= 10 m ,\  diameter= 10, \ r=\frac{diameter}{2} \ r=\frac{10}{2}\\ r=5

Putting these values in the previous equation , we get

10\ = \frac{22}{7} *5 *5*h\\ 14\ =\ 110*h\\h=\frac{110}{14} \\h=\frac{55}{2} \\\\h=27.5\  m

Therefore thickness is 27.5 m

7 0
4 years ago
A steel beam of mass 1975 kg and length 3 m is attached to the wall with a pin that can rotate freely on its right side. A cable
Nuetrik [128]

Answer:

a) 29062.125 N·m

b) 0 N·m

c) Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) T = 11186.02 N

Explanation:

We are given

Beam mass = 1975 kg

Beam length = 3 m

Cable angle = 60° above horizontal

a) We have the formula for torque given as follows;

Torque about the pin = Force × Perpendicular distance of force from pin

Where the force = Force due to gravity or weight, we have

Weight = Mass × Acceleration due to gravity = 1975 × 9.81 = 19374.75 N

Point of action of force = Midpoint for a uniform beam = length/2

∴ Point of action of force = 3/2 = 1.5 m

Torque due to gravity = 19374.75 N × 1.5 m = 29062.125 N·m

b) Torque about the pinned end due to the contact forces between the pin and the beam is given by the following relation;

Since the distance from pin to the contact forces between the pin and the beam is 0, the torque which is force multiplied by perpendicular distance is also 0 N·m

c) To find the expression for the tension force, T we find the sum of the moment forces about the pin as follows

Sum of moments about p is given as follows

∑M = 0 gives;

T·sin(θ) × L= M×L/2×g

Therefore torque due to tension is given by the following expression

Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}

d) Plugging in the values in the torque due to tension equation, we have;

3\times Tsin60 = \frac{1975\times 3\times 9.81}{2} = 29062.125

Therefore, we make the tension force, T the subject of the formula hence

T= \frac{29062.125}{3 \times sin(60)} = 11186.02 N

8 0
3 years ago
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