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nikitadnepr [17]
3 years ago
10

Which processes produce solute ions in a solution?

Chemistry
2 answers:
bonufazy [111]3 years ago
8 0

The answer for this question is B) Ionization and Dissociation because Dissociation happens, charged particles form (ions), and since the ions didn't exist before the substance was dissolved, this process is called IONIZATION.   It is the process that involves the formation of ions, a conversion of a substance into ions.



natali 33 [55]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

Ionization is defined as the production of ions in a solvent or solution. Whereas dissociation also means breaking of a chemical compound into ions or molecules when it is dissolved in water or polar solvent.

For example, when NaCl is dissolved in water then it will dissociate into sodium ions (Na^{+}) and chlorine (Cl^{-}) ions.

Hence, we can conclude that ionization and dissociation processes produce solute ions in a solution.

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How many grams of dry nh4cl need to be added to 2.50 l of a 0.800 m solution of ammonia, nh3, to prepare a buffer solution that
tia_tia [17]

Answer:

The correct answer is 574.59 grams.

Explanation:

Based on the given information, the number of moles of NH₃ will be,  

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pH + pOH = 14.00

pOH = 14.00 - pH

pOH = 14.00 - 8.53

pOH = 5.47

The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,  

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= 5.00 - log 1.8

= 5.00 - 0.26

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Based on Henderson equation:  

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pOH = pKb + [NH₄⁺]/[NH₃]

5.47 = 4.74 + log ([NH₄⁺]/[NH₃])

log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73

[NH₄⁺]/[NH₃] = 10^0.73= 5.37

[NH₄⁺ = 5.37 × 2 mol = 10.74 mol

Now the mass of dry ammonium chloride required is,  

mass of NH₄Cl = 10.74 mol × 53.5 g/mol

= 574.59 grams.  

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