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likoan [24]
2 years ago
9

Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.

Chemistry
1 answer:
Lilit [14]2 years ago
6 0

The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C          40.6       12                   \frac{40.6}{12} = 3.3                        \frac{3.3}{3.3} = 1

H          5.1          1                      \frac{5.1}{1} = 5.1                          \frac{5.1}{3.1} = 2

O         54.2       16                    \frac{54.2}{16} = 3.3                        \frac{3.3}{3.3} = 1

The Empirical formula of compound is C₁H₂O₁ or CH₂O

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}

   = \frac{118.084}{30}

   = 4

Molecular formula = n × Empirical formula

                              = 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

#SPJ1

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4.68x10⁹

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Kp is the equilibrium constant based on presure, and depends only on the gas substances. For a generic equation:

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The reaction given can be summed to form the third one:

C(s) + CO₂(g) ⇄ 2CO (g)  K'p = 1.30x10¹⁴

CO(g) + Cl₂(g) ⇄ COCl₂ (g) K''p = 6.00x10⁻³

We need to multiply the second reaction by 2, so CO will be simplified. If we multiplied a reaction for n, the new Kp will be (Kp)ⁿ, so:

C(s) + CO₂(g) ⇄ 2CO (g)  K'p = 1.30x10¹⁴

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The Kp of the reaction resulted by the sum will be: Kp = K'p*K''p

C(s) + CO₂(g) + 2Cl₂(g) ⇄  2CO(g) + 2COCl₂(g)

Kp = 1.30x10¹⁴ * (6.00x10⁻³)²

Kp = 1.30x10¹⁴*3.60x10⁻⁵

Kp = 4.68x10⁹

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<u>Answer:</u> The molarity of citric acid that is commercially available lemon juice is 0.416 M

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To calculate the concentration of acid, we use the equation given by neutralization reaction:

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n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

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Putting values in above equation, we get:

3\times M_1\times 20.00=1\times 1.751\times 14.26\\\\M_1=\frac{1\times 1.751\times 14.26}{3\times 20.00}=0.416M

Hence, the molarity of citric acid that is commercially available lemon juice is 0.416 M

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