Question

Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.

Answer 1

The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

What is Empirical Formula ?

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C          40.6       12                   $\frac{40.6}{12}$ = 3.3                        $\frac{3.3}{3.3} = 1$

H          5.1          1                      $\frac{5.1}{1}$ = 5.1                          $\frac{5.1}{3.1} = 2$

O         54.2       16                    $\frac{54.2}{16}$ = 3.3                        $\frac{3.3}{3.3} = 1$

The Empirical formula of compound is C₁H₂O₁ or CH₂O

How to find the Molecular formula of compound ?

Molecular formula = Empirical formula × n

$n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}$

   $= \frac{118.084}{30}$

   = 4

Molecular formula = n × Empirical formula

                              = 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

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