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2 years ago

Based on the way living things are organized ehat level combines to form organ ststems

Physics

1 answer:

Eddi Din [679]2 years ago

3 0

Answer:

Higher levels of organization are built from lower levels.

Molecules combine to form cells.

Cells combine to form tissues.

Tissues combine to form organs.

Organs combine to form organ systems,

and organ systems combine to form organisms.

Explanation:

Hope it helps.

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A lens is used to make an image of magnification -1.50. The image is 30.0 cm from the lens. What is the object’s distance (unit=

photoshop1234 [79]

Answer:

The object distance is 20cm

Explanation:

Given

Magnification = -1.5

Image distance = 30 cm.

Required

Object Distance

We can calculate the object's distance using magnification formula;

M = -V/U

Where M = Magnification = -1.50

V = Image Distance = 30cm

U = Object Distance

Substitute the above parameters in the formula above.

-1.50 = -30/U

Multiply both sides by -1

-1.50 * -1 = -30/U * -1

1.50 = 30/U

Multiply both sides by U

1.50 * U = 30/U * U

1.50U = 30

Divide through by 1.50

1.50U/1.50 = 30/1.50

U = 30/1.50

U = 20cm

Recall that U represented the object distance.

Hence, the object distance is 20cm

5 0

4 years ago

A research vessel is mapping the bottom of the ocean using sonar. It emits a short sound pulse called "ping" downward. The frequ

Svetradugi [14.3K]

Answer:

d = 4180.3m

wavelengt of sound is 0.251m

Explanation:

Given that

frequency of the sound is 5920 Hz

v=1485m/s

t=5.63s

let d represent distance from the vessel to the ocean bottom.

an echo travels a distance equivalent to 2d, that is to and fro after it reflects from the obstacle.

$velocity=\frac{distance}{time}\\\\ v=\frac{2d}{t} \\\\vt=2d\\\\d=\frac{vt}{2}$

$d=\frac{1485*5.63}{2}\\d= 4180.3m$

wavelengt of sound is $\lambda$ = v/f

= (1485)/(5920)

= 0.251 m

7 0

3 years ago

The equation for density is mass divided by volume if you pack more mass into a certain volume the density will?

Natali [406]

If you pack more mass into a certain volume, the density will increase.

8 0

4 years ago

Read 2 more answers

An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m lo

denis23 [38]

Answer:

The value is $T_m = 435.2 \ K$

Explanation:

From the question we are told that

The current is $I = 200 \ A$

The radius is $R = 0.001268 \ m$

The length of the wire is $L = 0.91 \ m$ \

The resistance is $R = 0.126 \ \Omega$

The outer surface temperature is $T _o = 422.1 \ K$

The average thermal conductivity is $\sigma = 22.5 W/mK$

Generally the heat generated in the stainless steel wire is mathematically represented as

$Q = \frac{Power}{ \pi r^2L}$

$Q = \frac{I^2 R}{ \pi r^2L}$

=> $Q = \frac{200^2 * 0.126}{3.142 * (0.001268)^2 * 0.91}$

=> $Q = 1.096*10^{9}\ W/m^3$

Generally the middle temperature is mathematically represented as

$T_m = T_o + \frac{Q * r^2 }{ 6 * \sigma }$

$T_m = 422.1 + \frac{1.096*10^{-9} * 0.001268^2}{6 * 22.5}$

$T_m = 435.2 \ K$

4 0

3 years ago

Magnetic and electric fields lab report guide

Digiron [165]

Answer:

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Explanation:

4 0

3 years ago

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