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vazorg [7]
3 years ago
12

What is the air change rate (ACH) for a 100 ft^2 (9.3 m^2) space with a 10 ft (3.0 m) ceiling and an airflow rate of 200 cfm (95

L/s)? A. B. C. 2 6 12
Engineering
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

The ACH is 12/h

Solution:

As per the question:

Area of the space, A_{s} = 100 ft^{2}

Height of the given space, h = 10 ft

Air flow rate, Q_{a} = 200 cfm

Now, to find the Air Change Rate (ACH):

We calculate the Volume of the given space:

V_{s} = A_{s}\times h = 100\times 10 = 1000 ft^{3}

Now, the ACH per min:

= \frac{V_{s}}{Q_{a}} = \frac{1000}{200} = 5/min

Now, ACH per hour:

= \frac{60}{5} = 12/h

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Explain about Absolute viscosity, kinematic viscosity and SUS?
ArbitrLikvidat [17]

Answer:

Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid  flow

Kinematic viscosity relates to the dynamic viscosity and density proportion.

SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity

Explanation:

Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid  flow, whereas Kinematic viscosity relates to the dynamic viscosity and density proportion. fluid with distinct kinematic viscosities may have similar dynamic viscosities and vice versa.Dynamic viscosity provides you details of  power required to make the fluid flow at some rate, however kinematic viscosity shows how quick the fluid moves when applying a certain force.

SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity when change with change in temperature. it is measured by using viscosimeter.

3 0
3 years ago
Is normally a large red cable connected to the battery
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Answer:

yes

Explanation:

its the ground cable

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A vertical cylinder (Fig. P3.227) has a 61.18-kg piston locked with a pin, trapping 10 L of R-410a at 10◦C with 90% quality insi
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4 0
3 years ago
Air expands through a turbine operating at steady state. At the inlet p1 = 150 lbf/in^2, T1 = 1400R and at the exit p2 = 14.8 lb
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Answer:

The power developed in HP is 2702.7hp

Explanation:

Given details.

P1 = 150 lbf/in^2,

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P2 = 14.8 lbf/in^2,

T2 = 700°R

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Using air table to obtain the values for h1 and h2 at T1 and T2

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h2 at T2 = 700°R = 167.6 Btu/h

Using;

Q - W + m(h1) - m(h2) = 0

W = Q - m (h2 -h1)

W = (-65000 Btu/h ) - 11 lb/s (167.6 - 342.9) Btu/h

W = (-65000 Btu/h ) - (-1928.3) Btu/s

W = (-65000 Btu/h ) * {1hr/(60*60)s} - (-1928.3) Btu/s

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W = 1910.24Btu/s

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W = 2702.7hp

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