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luda_lava [24]
3 years ago
8

Pennfoster Trades Safety test. Would appreciate the help. Thank you in advance. Check the screenshots below for the questions I'

d like help with.

Engineering
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:

11. D. Thermal burn

12. A. Shut off the electricity to the machine

13. A. Ingoing nip points

14. A. Workers performing one function all day from the same position

15. D. Before each shift

Explanation:

11. A thermal burn occurs when your body comes in contact with a hot object such as steam, boiling water or a hot wire. In this case, a shock will happen because you touched an electrical charged source with bare skin and because the wire in hot, you skin will burn due to dying of the skin cells that were exposed to high temperatures above normal.

12. An equipment such as a machine could be dangerous when operating, thus they are designed with safety equipment.In performing this process, an operator should first shut down the equipment.This can be improved by understanding the how to disconnect the machine, especially using  its on/off switch. The second step should be ensuring all external energy sources are disconnected.The third step follows disconnecting the secondary energy sources.This is called residual energy sources such as fumes that may need to be vented or trapped heat in the heating system.

13. In understanding machine hazards, in-running nip points are dangers that arise from rotating parts of a machine.These are the areas where moving parts of a machine advance towards each other or when a single moving part advances past a stationary section of a machine.For example where chains approach gears.

14. Repetitive motion disorder is a condition on body muscles caused by unnatural motions, incorrect working position, fatigue in body muscles and excess strain in oneself. The symptoms are tiredness and stiffness in the affected area.Applying self physiotherapy could help eliminate this condition.

15. An Aerial lift is any vehicle mounted device used in elevating operators working on towers, aerial ladders or extended platforms. These lifts have replaced ladders and scaffolding in similar jobs operations because of their flexibility and mobility. Hazards associated with aerial lifts include falling from elevated heights, tip-overs, falling objects from lifts , electrocutions and contacts with other objects. Pre-start inspection is a must before starting any operation on the lift.This is done on the vehicle itself and its lift components. The second step is performing the workplace inspection, to check things like the slopes of the area, presence of electric wires, debris at the place and factors such as weather conditions.

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Write the heat equation for each of the following cases:
jok3333 [9.3K]

Answer:

Explanation:

a) the steady-state, 1-D incompressible and no energy generation equation can be expressed as follows:

\dfrac{\partial^2T}{\partial x^2}=  \ 0  \  ;  \ if \  T = f(x)  \\ \\ \dfrac{\partial^2T}{\partial y^2}=  \ 0  \  ;  \ if \  T = f(y)  \\ \\ \dfrac{\partial^2T}{\partial z^2}=  \ 0  \  ;  \ if \  T = f(z)

b) For a transient, 1-D, constant with energy generation

suppose T = f(x)

Then; the equation can be expressed as:

\dfrac{\partial^2T}{\partial x^2} + \dfrac{Q_g}{k} = \dfrac{1}{\alpha} \dfrac{dT}{dC}

where;

Q_g = heat generated per unit volume

\alpha = Thermal diffusivity

c) The heat equation for a cylinder steady-state with 2-D constant and no compressible energy generation is:

\dfrac{1}{r}\times \dfrac{\partial}{\partial r }( r* \dfrac{\partial \ T }{\partial \ r}) + \dfrac{\partial^2 T}{\partial z^2 }= 0

where;

The radial directional term = \dfrac{1}{r}\times \dfrac{\partial}{\partial r }( r* \dfrac{\partial \ T }{\partial \ r}) and the axial directional term is \dfrac{\partial^2 T}{\partial z^2 }

d) The heat equation for a wire going through a furnace is:

\dfrac{\partial ^2 T}{\partial z^2} = \dfrac{1}{\alpha}\Big [\dfrac{\partial ^2 T}{\partial ^2 t}+ V_z \dfrac{\partial ^2T}{\partial ^2z} \Big ]

since;

the steady-state is zero, Then:

\dfrac{\partial ^2 T}{\partial z^2} = \dfrac{1}{\alpha}\Big [ V_z \dfrac{\partial ^2T}{\partial ^2z} \Big ]'

e) The heat equation for a sphere that is transient, 1-D, and incompressible with energy generation is:

\dfrac{1}{r} \times \dfrac{\partial}{\partial r} \Big ( r^2 \times \dfrac{\partial T}{\partial r} \Big ) + \dfrac{Q_q}{K} = \dfrac{1}{\alpha}\times \dfrac{\partial T}{\partial t}

4 0
3 years ago
What are the factors that influence the power input to the compressor?
Lena [83]

Answer:

option e is correct answer

5 0
2 years ago
Q9. A cylindrical specimen of a metal alloy 54.8 mm long and 10.8 mm in diameter is stressed in tension. A true stress of 365 MP
wolverine [178]

Answer:

σ = 391.2 MPa

Explanation:

The relation between true stress and true strain is given as:

σ = k εⁿ

where,

σ = true stress = 365 MPa

k = constant

ε = true strain = Change in Length/Original Length

ε = (61.8 - 54.8)/54.8 = 0.128

n = strain hardening exponent = 0.2

Therefore,

365 MPa = K (0.128)^0.2

K = 365 MPa/(0.128)^0.2

k = 550.62 MPa

Now, we have the following data:

σ = true stress = ?

k = constant = 550.62 MPa

ε = true strain = Change in Length/Original Length

ε = (64.7 - 54.8)/54.8 = 0.181

n = strain hardening exponent = 0.2

Therefore,

σ = (550.62 MPa)(0.181)^0.2

<u>σ = 391.2 MPa</u>

7 0
3 years ago
When the electrical connection to the alternator from the battery is not tight, it can cause?
Oksi-84 [34.3K]

Answer:

affects the flow of electricity

Explanation:

A loose battery terminal affects the flow of electricity. There is less power going to the electrical systems and the vehicle will not start or start sluggishly. Also, a loose battery terminal causes the car's electrical components like navigation, car lights, and audio among others to dim or fail completely.

3 0
2 years ago
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
KIM [24]

Answer:

The answer is below

Explanation:

a) The work done is equal to the loss in kinetic energy (KE)

Change in kinetic energy (ΔKE) = Final kinetic energy - initial kinetic energy

Final KE = \frac{1}{2}mv_f^2

But the final velocity is 0 (at rest). Hence:

Final KE = \frac{1}{2}mv_f^2=\frac{1}{2}m(0)^2=0

ΔKE = 0 - K = -K

W = ΔKE = -K

Also, the work done (W) = charge (q) * distance (d) * electric field intensity (E)

W = qEd

but q = -e, hence:

W = -e * E * d

Using:

W = ΔKE

-e * E * d = -K

E= K / (e * d)

b) The electric field is in the direction of the electrons motion

7 0
2 years ago
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