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luda_lava [24]
4 years ago
8

Pennfoster Trades Safety test. Would appreciate the help. Thank you in advance. Check the screenshots below for the questions I'

d like help with.

Engineering
1 answer:
AlexFokin [52]4 years ago
5 0

Answer:

11. D. Thermal burn

12. A. Shut off the electricity to the machine

13. A. Ingoing nip points

14. A. Workers performing one function all day from the same position

15. D. Before each shift

Explanation:

11. A thermal burn occurs when your body comes in contact with a hot object such as steam, boiling water or a hot wire. In this case, a shock will happen because you touched an electrical charged source with bare skin and because the wire in hot, you skin will burn due to dying of the skin cells that were exposed to high temperatures above normal.

12. An equipment such as a machine could be dangerous when operating, thus they are designed with safety equipment.In performing this process, an operator should first shut down the equipment.This can be improved by understanding the how to disconnect the machine, especially using  its on/off switch. The second step should be ensuring all external energy sources are disconnected.The third step follows disconnecting the secondary energy sources.This is called residual energy sources such as fumes that may need to be vented or trapped heat in the heating system.

13. In understanding machine hazards, in-running nip points are dangers that arise from rotating parts of a machine.These are the areas where moving parts of a machine advance towards each other or when a single moving part advances past a stationary section of a machine.For example where chains approach gears.

14. Repetitive motion disorder is a condition on body muscles caused by unnatural motions, incorrect working position, fatigue in body muscles and excess strain in oneself. The symptoms are tiredness and stiffness in the affected area.Applying self physiotherapy could help eliminate this condition.

15. An Aerial lift is any vehicle mounted device used in elevating operators working on towers, aerial ladders or extended platforms. These lifts have replaced ladders and scaffolding in similar jobs operations because of their flexibility and mobility. Hazards associated with aerial lifts include falling from elevated heights, tip-overs, falling objects from lifts , electrocutions and contacts with other objects. Pre-start inspection is a must before starting any operation on the lift.This is done on the vehicle itself and its lift components. The second step is performing the workplace inspection, to check things like the slopes of the area, presence of electric wires, debris at the place and factors such as weather conditions.

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Explanation:

Torque is the cross product of the radius vector and force vector:

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τ = r · Ftangential

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State 3 advantages and 3 disadvantages of unit rate contract​
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In a heat-treating process, a 1-kg metal part, initially at 1075 K, is quenched in a closed tank containing 100 kg of water, ini
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attached below

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3 years ago
Answer the following questions, and very briefly explain your answer:
alexandr1967 [171]

Answer:

A) micro defects are left behind on the surface of metal components during the manufacturing process. These defects, in the form of micro-cracks or pits, becomes initiation sites for crack propagation or corrosion. Removing these imperfections on the surface of metal parts by electroplating greatly improves the life of metal components.

B) it will reduce fatigue crack growth.

Dispersion hardening involves the inclusion of small, hard particles in the metal, thus restricting the movement of dislocations, and thereby raising the strength properties. In dispersion hardening it is assumed that the precipitates do not deform with the matrix and that a moving dislocation bypasses the obstacles (precipitates) by moving in the clean pieces of crystal between the precipitated particles.

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3 years ago
Volume of sale (i.e., the number of parts sold) is a factorwhen determining which
nadya68 [22]

Answer: N has to be lesser than or equal to 1666.

Explanation:

Cost of parts N in FPGA = $15N

Cost of parts N in gate array = $3N + $20000

Cost of parts N in standard cell = $1N + $100000

So,

15N < 3N + 20000 lets say this is equation 1

(cost of FPGA lesser than that of gate array)

 Also. 15N < 1N + 100000  lets say this is equation 2  

(cost of FPGA lesser than that of standardcell)

Now

From equation 1

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From equation 2

14N < 100000

N < 7142.85

AT the same time, Both conditions must hold true

So N <= 1666 (Since N has to be an integer)

N has to be lesser than or equal to 1666.

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3 years ago
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