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1 year ago

If a bearing needs 4. 0 s to solidify enough for impact, how high must the tower be?.

Engineering

1 answer:

maks197457 [2]1 year ago

6 0

The height of the tower is equal to 78.4 meters.
The bearing's impact velocity is equal to 39.2 m/s.

<h3>How to determine the height of the tower?</h3>

In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

Where:

S represents the distance or height.
u represents the initial velocity.
a represents the acceleration.
t represents the time.

Substituting the given parameters into the formula, we have;

S = S₀ + ut - ½gt²

0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²

0 = S₀ - 4.9 × 16.0

Height, S₀ = 78.4 meters.

<h3>How to calculate the bearing's impact velocity?</h3>

In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

V = u - at

V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

Read more on velocity here: brainly.com/question/19365526

#SPJ1

Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

b. What is the bearing's impact velocity?

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Our data are given by

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Note that the pressure to 38°C is 0.06626 bar

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$\dot{m} = \frac{0.6626*10^{5}*510}{287*311}$

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Therfore the mass flow rate at which water condenses, then

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Re-arrange to find $\dot{m_v}$

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$\dot{m_v} = 0.97*37.85$

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$H= H_a +H_v$

Where,

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3 years ago

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Answer:

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// Note : This is an in efficient way to multipy!

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