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Lerok [7]
2 years ago
10

An animal shelter has a total of 5 * 47 animals comprised of cats, dogs, and rabbits. If the number of rabbits is 5 less than on

e half the number of cats, and there are 20 more cats than dogs, how many dogs are at the shelter?
Mathematics
1 answer:
Dvinal [7]2 years ago
5 0

The number of dogs in the animal shelter which comprise of cats, dogs, and rabbits is 84 dogs.

<h3>Equation</h3>

Total animals = 5 × 47

= 235

  • Number of rabbits = 1/2(d + 20) - 5
  • Number of cats = d + 20
  • Number of dogs = d

235 = d + (d + 20) + 1/2(d + 20) - 5

235 = d + d + 20 + 1/2d + 10 - 5

235 = 2 1/2d + 25

235 - 25 = 2 1/2d

210 = 2 1/2d

d = 210 ÷ 2 1/2

d = 210 ÷ 5/2

= 210 × 2/5

= 420/5

d = 84 dogs

Learn more about equation:

brainly.com/question/2972832

#SPJ1

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

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In this question, we have that:

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