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Wittaler [7]
2 years ago
6

What is the order in which electrons start filling the orbitals?

Chemistry
1 answer:
emmainna [20.7K]2 years ago
4 0

a. 1s 2s 2p 3s 3p 4s 3d 4p is the correct option.

This gives the following order to fill the orbit: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, (8s, 5g, 6f, 7d, 8p, and 9s)

Aufbau's principle states that electrons fill low-energy atomic orbitals before they fill high-energy atomic orbitals. .. By following this rule, you can predict the electron configuration of an atom or ion.

There may be two electrons at the maximum of one orbit. Since the s subplane has only one orbit, it can hold up to two electrons. The p subplane has three orbitals, so it can hold up to six electrons. The d-subplane has five orbitals, so it can hold up to 10 electrons.

Learn more about electrons here:brainly.com/question/11316046

#SPJ4

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Answer:

All colors except blue are absorbed while blue is reflected. We

only see blue

Explanation:

When you go and see something blue as the sky, all of the colors are absorbed except blue. That is how we see colors

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3 years ago
1. A sample of gas has an initial volume of 25 L and an initial pressure of 123.5 kPa. If the pressure changes to
sveta [45]

Answer:

\large \boxed{\text{17.mL}}

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{123.5 kPa}\qquad & V_{1} &= & \text{25 L} \\p_{2}& =& \text{179.9 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:  

\begin{array}{rcl}123.5 \times 25 & =& 179.9V_{2}\\3088 & = & 179.9V_{2}\\V_{2} & = &\dfrac{3088}{179.9}\\\\& = &\textbf{17 L}\\\end{array}\\\text{The new volume of the gas is } \large \boxed{\textbf{17 L}}

6 0
3 years ago
A rift valley forms at a
vovikov84 [41]
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4 0
3 years ago
Please help me balance:<br>_NaNO3 + _PbO_ ➡️ Pb(NO3)2 + _Na2O
KengaRu [80]

Answer:

The balanced reaction is given by,

2NaN(O)3 + PbO ⇒ Pb(NO3)2 + Na2O

Explanation:

The reaction is as given.

Lets count the number of each elements in the reaction.

<em>In reactant side, number of sodium atoms are 1 , lead are 1, nitrogen are 1 and oxygen are 4.</em>

<em>in product side, number of sodium atoms are 2 , lead are 1 , nitrogen are 2 and oxygen are 7.</em>

<em>So we need to balance sodium and oxygen atoms in the reaction.</em>

<em>There is deficient of sodium and oxygen atoms on reactant side</em>.

Thus, multiply (NaNO3) by 2.

<em>Thus, sodium atoms become 2 , nitrogen 2 and oxygen 6. Total 7 oxygen atoms.</em>

Thus, the balanced reaction is,

2NaN(O)3 + PbO ⇒ Pb(NO3)2 + Na2O

7 0
3 years ago
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