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maksim [4K]
3 years ago
5

Which of the following conditions characterizes atmosphere lll

Chemistry
2 answers:
djverab [1.8K]3 years ago
4 0

nitrogen-rich and oxygen poor is the correct answer

CaHeK987 [17]3 years ago
3 0

I believe that this question has the following choices:

 

<span>>  hydrogen- and helium-rich </span>
<span>>  water vapor- and carbon dioxide-rich </span>
<span>>  nitrogen- and oxygen-rich </span>
<span>>  nitrogen-rich and oxygen-poor </span>

 

The correct answer among the choices is that atmosphere III is:

<span>> nitrogen- and oxygen-rich </span>

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Potassium + water = potassium hydroxide + hydrogen​
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2 years ago
The map shows the average high temperatures in July for two cities in Texas.
alexira [117]

Answer:

Highest temperature which was recorded in Texas was 40 degrees.

Explanation:

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3 years ago
The statements in the table summarize what Johannes Kepler stated in the early 1600s about the motion of planets.
SIZIF [17.4K]

Answer:

it's law

Explanation:

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4 0
3 years ago
How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
3 years ago
Using the law of conservation of energy what is the kinetic energy at D
seraphim [82]

Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.

Explanation:

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3 0
2 years ago
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