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maksim [4K]
3 years ago
5

Which of the following conditions characterizes atmosphere lll

Chemistry
2 answers:
djverab [1.8K]3 years ago
4 0

nitrogen-rich and oxygen poor is the correct answer

CaHeK987 [17]3 years ago
3 0

I believe that this question has the following choices:

 

<span>>  hydrogen- and helium-rich </span>
<span>>  water vapor- and carbon dioxide-rich </span>
<span>>  nitrogen- and oxygen-rich </span>
<span>>  nitrogen-rich and oxygen-poor </span>

 

The correct answer among the choices is that atmosphere III is:

<span>> nitrogen- and oxygen-rich </span>

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What is the nature of the Ca-Cl bond in a molecule of calcium chloride (CaCl2) if the electronegativity value of calcium is 1.0
nevsk [136]
Ca-Cl is an ionic bond. We know this because the difference between their electronegativities is 2.16.The electronegativity tells us which atom will attract the electron more than the other. Hence, chlorine attracts the electron a lot more than the calcium.A difference of more than 1.6 (or 1.7 depending on the source) implies that the electrons are so unevenly shared, that the bond is ionic, rather than polar covalent.

3 0
3 years ago
A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a
san4es73 [151]

Answer:

A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a simple substitution reaction or simple displacement reaction.

Explanation:

A simple substitution reaction or simple displacement reaction, called single-displacement reaction, is a reaction in which an element of a compound is substituted by another element involved in the reaction. The starting materials are always pure elements and an aqueous compound. And a new pure aqueous compound and a different pure element are generated as products. The general form of a simple substitution reaction is:

AB + C → A +BC

where C and A are pure elements; C replaces A within compound AB to form a new co, placed CB and elementary A.

So, in a Single replacement reaction an uncombined element replaces an element.

<u><em>A chemical reaction in which an uncombined element replaces an element that is part of a compound is called a simple substitution reaction or simple displacement reaction.</em></u>

3 0
3 years ago
What is the difference between an atone and a molecule
Step2247 [10]

Answer:

Explanation:

Molecules contain two or more atoms and are held together by covalent bonds, whereas compounds are held together by ionic bonds. Two or more elements bonded together through ionic attraction. ... The atoms within a compound also must be different from each other, whereas a molecule can consist of only one element

8 0
3 years ago
Please help and show work, i will mark you brainlest
Natali [406]

Answer:

7x-2(3-4)-2

Pls help

Explanation:

8 0
3 years ago
1.20 x 10^22 molecules NaOH to gram
Trava [24]

Answer:

\boxed {\boxed {\sf 0.797 \ g \ NaOH}}

Explanation:

<u>1. Convert Molecules to Moles</u>

First, we must convert molecules to moles using Avogadro's Number: 6.022*10²³. This tells us the number of particles in 1 mole of a substance. In this case, the particles are molecules of sodium hydroxide.

\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Multiply by the given number of molecules.

1.20*10^{22} \ molecules \ NaOH *\frac {6.022*10^{23} \ molecules \ NaOH} {1 \ mol \ NaOH}}

Flip the fraction so the molecules cancel out.

1.20*10^{22} \ molecules \ NaOH *\frac {1 \ mol \ NaOH} {6.022*10^{23} \ molecules \ NaOH}}

1.20*10^{22}  *\frac {1 \ mol \ NaOH} {6.022*10^{23}}}

\frac {1.20*10^{22} \ mol \ NaOH} {6.022*10^{23}}}

0.0199269345732 \ mol \ NaOH

<u>2. Convert Moles to Grams</u>

Next, we convert moles to grams using the molar mass.

We must calculate the molar mass using the values on the Periodic Table. Look up each individual element.

  • Na: 22.9897693 g/mol
  • O: 15.999 g/mol
  • H: 1.008 g/mol

Since the formula has no subscripts, we can simply add the molar masses.

  • NaOH: 22.9897693+15.999+1.008=39.9967693 g/mol

Use this as a ratio.

\frac {39.9967693 \ g  \ NaOH }{1 \ mol \ NaOH}

Multiply by the number of moles we calculated.

0.0199269345732 \ mol \ NaOH*\frac {39.9967693 \ g  \ NaOH }{1 \ mol \ NaOH}

The moles of sodium hydroxide cancel.

0.0199269345732 *\frac {39.9967693 \ g  \ NaOH }{1}

0.0199269345732 *39.9967693 \ g  \ NaOH

0.79701300498 \ g \ NaOH

The original measurement of molecules has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 0 tells us to leave the 7 in the hundredth place.

0.797 \ g \ NaOH

1.20*10²² molecules of sodium hydroxide is approximately 0.797 grams.

4 0
3 years ago
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