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maksim [4K]
3 years ago
5

Which of the following conditions characterizes atmosphere lll

Chemistry
2 answers:
djverab [1.8K]3 years ago
4 0

nitrogen-rich and oxygen poor is the correct answer

CaHeK987 [17]3 years ago
3 0

I believe that this question has the following choices:

 

<span>>  hydrogen- and helium-rich </span>
<span>>  water vapor- and carbon dioxide-rich </span>
<span>>  nitrogen- and oxygen-rich </span>
<span>>  nitrogen-rich and oxygen-poor </span>

 

The correct answer among the choices is that atmosphere III is:

<span>> nitrogen- and oxygen-rich </span>

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How many moles are in a 111.5 gram sample of sodium chloride, NaCl?
Katarina [22]

Answer: 1.91 moles

Explanation:

First you want to find the molar mass of NaCL

Na = 22.99g  Cl = 35.45g

22.99g + 35.45g = 54.44g

Then divide 111.5g by 54.44g and this will give you moles.

5 0
2 years ago
Air at 25°C with a dew point of 10 °C enters a humidifier. The air leaving the unit has an absolute humidity of 0.07 kg of water
madreJ [45]

Explanation:

The given data is as follows.

         Temperature of dry bulb of air = 25^{o}C

          Dew point = 10^{o}C = (10 + 273) K = 283 K

At the dew point temperature, the first drop of water condenses out of air and then,

        Partial pressure of water vapor (P_{a}) = vapor pressure of water at a given temperature (P^{s}_{a})

Using Antoine's equation we get the following.

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{T(K) - 46.854}

            ln (P^{s}_{a}) = 16.26205 - \frac{3799.887}{283 - 46.854}

                               = 0.17079

                   P^{s}_{a} = 1.18624 kPa

As total pressure (P_{t}) = atmospheric pressure = 760 mm Hg

                                   = 101..325 kPa

The absolute humidity of inlet air = \frac{P^{s}_{a}}{P_{t} - P^{s}_{a}} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                  \frac{1.18624}{101.325 - 1.18624} \times \frac{18 kg H_{2}O}{29 \text{kg dry air}}

                 = 0.00735 kg H_{2}O/ kg dry air

Hence, air leaving the humidifier has a has an absolute humidity (%) of 0.07 kg H_{2}O/ kg dry air.

Therefore, amount of water evaporated for every 1 kg dry air entering the humidifier is as follows.

                 0.07 kg - 0.00735 kg

              = 0.06265 kg H_{2}O for every 1 kg dry air

Hence, calculate the amount of water evaporated for every 100 kg of dry air as follows.

                0.06265 kg \times 100

                  = 6.265 kg

Thus, we can conclude that kg of water the must be evaporated into the air for every 100 kg of dry air entering the unit is 6.265 kg.

3 0
3 years ago
Select only one most suitable description
Annette [7]
I believe it's a pure element
3 0
2 years ago
Contrast mixtures with pure substances
dimaraw [331]

<em>Mixtures</em>

  • consist of two or more substances
  • have a variable composition
  • can be separated into their components by physical means

<em>Pure substance</em>s

  • consist of a single element or compound
  • have a definite and constant composition
  • cannot be separated into their components by physical means
7 0
3 years ago
What change would increase the amount of gas able to be dissolved in a given amount of liquid water?
butalik [34]
It would be the change in pressure that would <span>increase the amount of gas able to be dissolved in a given amount of liquid water. Increasing the pressure of a system would allow more gas to be dissolved into a liquid. Hope this answers the question. Have a nice day.</span>
3 0
2 years ago
Read 2 more answers
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