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3 years ago

Which of following is true of liquids?

Chemistry

2 answers:

Mashutka [201]3 years ago

7 0

Answer:

The particles move at a high rate of speed.

The particles have a medium amount of kinetic energy and slide past one another.

Explanation:

The options that are true about liquids are A. The particles move at a high rate of speed and B. The particles have a medium amount of kinetic energy and slide past one another, because particles in a liquids are slippery, so they slide past one another. This is how liquids move around. The particles help it move around.

zvonat [6]3 years ago

6 0

Answer:

The particles have a medium amount of kinetic energy and slide past one another

Explanation:

If particles move at a high rate of speed its gas, and if they vibrate in place and they have a fixed volume and shape its probably a solid. So a medium amount of kinetic enery is correct.

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Rn-222 has a half-life of 3.82 days. If 25.0 g of Radon-22 was originally present, approximately how many grams would be left af

horsena [70]

Answer:

Approximately 0.39 g or 0.4 g if you're rounding up

Explanation:

15/3.82 = 3.92

Let's round that up to 4

That means 15 days is around 4 half lives

4 half lives means 1/16 of the original mass will be left

25/16 = 0.390625

6 0

3 years ago

A student has a 2.19 L bottle that contains a mixture of O 2 , N 2 , and CO 2 with a total pressure of 5.57 bar at 298 K . She k

Sergeeva-Olga [200]

<u>Answer:</u> The partial pressure of oxygen gas is 2.76 bar

<u>Explanation:</u>

To calculate the number of moles, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 5.57 bar

V = Volume of the gas = 2.19 L

T = Temperature of the gas = 298 K

R = Gas constant = $0.0831\text{ L bar }mol^{-1}K^{-1}$

n = Total number of moles = ?

Putting values in above equation, we get:

$5.57bar\times 2.19L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{5.57\times 2.19}{0.0831\times 298}=0.493mol$

To calculate the mole fraction of carbon dioxide, we use the equation given by Raoult's law, which is:

$p_{A}=p_T\times \chi_{A}$ ........(1)

where,

$p_A$ = partial pressure of carbon dioxide = 0.318 bar

$p_T$ = total pressure = 5.57 bar

$\chi_A$ = mole fraction of carbon dioxide = ?

Putting values in above equation, we get:

$0.318bar=5.57bar\times \chi_{CO_2}\\\\\chi_{CO_2}=\frac{0.381}{5.57}=0.0571$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

We are given:

Moles of nitrogen gas = 0.221 moles

Mole fraction of nitrogen gas, $\chi_{N_2}=\frac{0.221}{0.493}=0.448$

Calculating the partial pressure of oxygen gas by using equation 1, we get:

Mole fraction of oxygen gas = (1 - 0.0571 - 0.448) = 0.4949

Total pressure of the system = 5.57 bar

Putting values in equation 1, we get:

$p_{O_2}=5.57bar\times 0.4949\\\\p_{O_2}=2.76bar$

Hence, the partial pressure of oxygen gas is 2.76 bar

6 0

3 years ago

Does anyone have geometry on edg ??!!!

AfilCa [17]

Teblgdjfjkftmdjrnrbkfshkk

3 0

2 years ago

Pls halp. i give brainliest to 1st correct answer

Kruka [31]

Answer:

C is correct

Explanation: Heat describes the transfer of thermal energy between molecules within a system and is measured in Joules. Heat measures how energy moves or flows. ... Temperature describes the average kinetic energy of molecules within a material or system and is measured in Celsius (°C), Kelvin(K), Fahrenheit (°F), or Rankine (R)

4 0

3 years ago

Jorge has an unknown mineral. The mineral has a mass of 21 grams and has a volume of 3cm3. Calculate density and find his unknow

DerKrebs [107]

Answer:

7g/cm³

Explanation:

Given parameters:

Mass of the mineral = 21g

Volume = 3cm³

Unknown:

Density of the mineral = ?

Solution:

Density of a substance is the mass per unit volume of the substance.

Density = $\frac{mass}{volume}$

Now insert the given parameters and solve;

Density = $\frac{21}{3}$ = 7g/cm³

The mineral with a density of 7g/cm³ is Galena, an ore of lead.

6 0

3 years ago