Answer:
t = 1.659s
Explanation:
We can use the kinematics equations to solve this questions:
v = u + at
where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement
a) Given information from the question,
u = (Convert km/h to m/s first)
a =
s = 35m
Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.
b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.
v = u + at
22.761 = 19.444 + 2t
2t = 22.761 - 19.444
t =
t = 1.659s
Answer:
The ratio of the orbital time periods of A and B is
Solution:
As per the question:
The orbit of the two satellites is circular
Also,
Orbital speed of A is 2 times the orbital speed of B
(1)
Now, we know that the orbital speed of a satellite for circular orbits is given by:
where
R = Radius of the orbit
Now,
For satellite A:
Using eqn (1):
(2)
For satellite B:
(3)
Now, comparing eqn (2) and eqn (3):
Answer:
0.18216 T
Explanation:
N = Number of turns = 219
A = Area =
r = Radius = 1 cm
= Angular speed =
Maximum emf is given by
The strength of the magnetic field is 0.18216 T
Answer:
58.5 m
Explanation:
First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.
The initial vertical velocity of the ball is
where
u = 21.5 m/s is the initial speed
is the angle
Substituting,
The vertical position of the ball at time t is given by
where
h = 13.5 m is the initial heigth
is the acceleration of gravity (negative sign because it points downward)
The ball reaches the water when y = 0, so
Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.
The horizontal velocity of the ball is
And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows: