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Likurg_2 [28]
3 years ago
11

Compared with a car moving at some original speed, how much work must the brakes of a car supply to stop a car that is moving tw

ice as fast.
Physics
1 answer:
vovangra [49]3 years ago
8 0

Answer:

Compared with a car moving at some original speed, four times work must the brakes of a car supply to stop a car that is moving twice as fast. Stopping distance should also be four times.

Explanation:

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An acetal polymer block is fixed to the rigid plates at its top and bottom surfaces. If the top plate displaces 2 mm horizontall
Taya2010 [7]

Answer:

The shear modulus of the polymer is 5 MPa

Solution:

As per the question:

displacement of the top plate, d = 2 mm = 0.002 m

Horizontal Force, P = 2 kN = 2000 N

Width of the block, w = 100 mm = 0.1 m

By small angle analysis:

Angle, \gamma = \frac{2}{200} = 0.01 rad

Now,

Stress, \tau = \frac{P}{Area} = \frac{2000}{0.4\times 0.1} = 50000 Pa

G = \frac{\tau}{\gamma} = \frac{50000}{0.01} = 5 MPa

3 0
3 years ago
Why are the surface features of the moon essentially unaltered since youth
zmey [24]

Because there is no wind, rain, snow, sleet, or people to wear them down,
and no rivers, streams, or floods to cover them over.

8 0
3 years ago
2a. A wave has a frequency of 50 Hz and a wavelength of 0.10 m. How do you find the wave speed? *
KIM [24]
D is it so go with it
5 0
3 years ago
What is the mass of 5.4 moles of copper ?
Helen [10]
343.1484 grams. this is your answer.
3 0
4 years ago
A force F = (cx - 3.00x^2)i^ acts on a virus as the virus moves along an x axis, with F measured in Newtons, x in meters, and c
Ket [755]

Answer:

c = 4

Explanation:

From work-energy theorem KE = workdone.

Given F = (cx - 3.00x²)i

W = ∫Fdx = ∫(cx - 3.00x²)dx = cx²/2 –3.00x³/3 + A

W = cx²/2 –x³ + A

Where A is a constant

At x = 0, KE = 20J

So W = 20J at x = 0

20 = c×0 - 0 +A

A = 20

So W = cx²/2 –x³ + 20

Also when x = 3.00m, W = KE = 11J

So

11 = c×3²/2 – 3³ + 20

11 = 4.5c – 7

4.5c = 11 + 7

4.5c = 18

c = 18/4.5 = 4

c = 4

6 0
4 years ago
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