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3 years ago

What type of tide occurs on a full moon or a new moon?

2 answers:

6 0

Spring tides will occur during a full moon and an new moon. The sun and moon are on a certain angle causing these tides to be neap tides, they aren't high tide nor are they low tides so you would verbalize they are in between and that is why it is called neap tides as well.

Bezzdna [24]3 years ago

3 0

Spring tides occur during full and new moons.

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if a big stone and a small stone is dropped simultaneously from the certain height. they fall together why??

Alenkasestr [34]

Answer:

they are both stones that is why

4 0

3 years ago

Read 2 more answers

In a closed ring a and in an open ring magnet are falling along the x axis of thrme ring .the current generated in a and b have

zhenek [66]

Answer:

ALL AWNERS HERE

Explanation:

https://quizlet.com/449884025/test-3-physics-2-flash-cards/

8 0

3 years ago

A block sliding across a level surface has a mass of 2.5 kg and a mechanical energy of 20 joules. What is its velocity?

tia_tia [17]

Hi!

The energy of the block is 4 m/s

To calculate this, you need to use the equation for kinetic energy. The block is sliding (i.e. it's moving). If the object is sliding across a level surface, the only energy it has is kinetic energy, because there is no change in potential energy (which changes with height). So, the mechanical energy will be pure kinetic energy. The equation is the following, derived from the expression for kinetic energy:

$v= \sqrt{ \frac{2*Ke}{m}}=\sqrt{ \frac{2*20 (kg*m^{2}*s^{-2}) }{2,5kg}}=4 m/s$

Have a nice day!

8 0

3 years ago

What is the name of the force that acts between any two objects because of<br>their masses?

svetoff [14.1K]

Answer:

Explanation:

The force of attraction between 2 masses.

4 0

3 years ago

A person carries a plank of wood 2.00 m long with one hand pushing down on it at one end with a force f1 and the other hand hold

slega [8]

Answer:

F₁ = 4,120.2 N

F₂ = 3,924N

Explanation:

1) Balance of angular momentum around the end where F₁ is applied.

F₂ × 0.5m - F₁ × 0 = mass × g × 1m

⇒ F2 × 0.5 m= 20 kg × 9.81 m/s² × 1 m = 1,962 N×m

F₂ = 196.2 Nm / 0.5m = 3,924 N

2) Balance of forces

F₁ - F₂ = mg

F₁ = F₂ + mg = 3,924N + 20kg (9.81 m/s²) = 4,120.2 N

4 0

3 years ago