Answer:
NaCl neutral
Na₂SO₄ basic
NaHCO₃ basic
K₃PO₄ basic
Na₃C₆H₅O₇ basic
CaCl₂ neutral
Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water.
Oxalic acid (C₂H₂O₄) dissolves and dissociates in water
Explanation:
<em>Identify each item as being acidic, basic, or neutral when dissolved in water. If a particular ingredient does make an acidic or basic solution, describe how this occurs.</em>
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NaCl
When NaCl is dissolved in water the resulting solution is neutral.
Na₂SO₄
When Na₂SO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the SO₄²⁻ ion.
SO₄²⁻(aq) + H₂O(l) ⇄ HSO₄⁻(aq) + OH⁻(aq)
NaHCO₃
When NaHCO₃ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the HCO₃⁻ ion.
HCO₃⁻(aq) + H₂O(l) ⇄ H₂CO₃(aq) + OH⁻(aq)
K₃PO₄
When K₃PO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the PO₄³⁻ ion.
PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)
Na₃C₆H₅O₇ (sodium citrate)
When Na₃C₆H₅O₇ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the C₆H₅O₇³⁻ ion.
C₆H₅O₇³⁻(aq) + H₂O(l) ⇄ C₆H₆O₇²⁻(aq) + OH⁻(aq)
CaCl₂
When CaCl₂ is dissolved in water the resulting solution is neutral.
Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water according to the following equation:
Na₂C₂O₄(aq) ⇄ 2 Na⁺(aq) + C₂O₄²⁻(aq)
Oxalic acid (C₂H₂O₄) dissolves and dissociates in water according to the following equation:
C₂H₂O₄(aq) ⇄ C₂HO₄⁻(aq) + H⁺(aq)
